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Python | Consecutive duplicates all elements deletion in list

  • Last Updated : 05 Sep, 2019

Sometimes, while working with Python list, a problem can occur to filter list to remove duplicates. The solution to this has been discussed before. But sometimes, we may have a problem in which we need to delete the duplicate and element itself if it occurs more than 1 in consecution. This type of problem can occur in day-day programming and other applications as well. Let’s discuss a shorthand in which this task can be performed.

Method : Using list comprehension + groupby() + sum()
This task can be performed using the combination of above functions. The first step is grouping the elements into duplicates using groupby(), and then if they occur more than 0 times, remove them, i.e include only those elements that occur once. This counting task is handled by sum()




# Python3 code to demonstrate working of
# Consecutive duplicates all elements deletion in list
# using list comprehension + sum() + groupby()
from itertools import groupby
  
# initialize list
test_list = [1, 1, 3, 4, 4, 4, 5, 6, 6, 7, 8, 8, 6]
  
# printing original list
print("The original list is : " + str(test_list))
  
# Consecutive duplicates all elements deletion in list
# using list comprehension + sum() + groupby()
res = [i for i, j in groupby(test_list) if sum(1 for x in j) < 2]
  
# printing result
print("List after consecutive duplicates elements deletion : " + str(res))
Output :
The original list is : [1, 1, 3, 4, 4, 4, 5, 6, 6, 7, 8, 8, 6]
List after consecutive duplicates elements deletion : [3, 5, 7, 6]

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