Sometimes, while working with Python list, a problem can occur to filter list to remove duplicates. The solution to this has been discussed before. But sometimes, we may have a problem in which we need to delete the duplicate and element itself if it occurs more than 1 in consecution. This type of problem can occur in day-day programming and other applications as well. Let’s discuss a shorthand in which this task can be performed.
Method : Using list comprehension +
groupby() + sum()
This task can be performed using the combination of above functions. The first step is grouping the elements into duplicates using
groupby(), and then if they occur more than 0 times, remove them, i.e include only those elements that occur once. This counting task is handled by
The original list is : [1, 1, 3, 4, 4, 4, 5, 6, 6, 7, 8, 8, 6] List after consecutive duplicates elements deletion : [3, 5, 7, 6]
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