Python – Concatenate Maximum Tuples
Given a tuple list with string and its magnitude, the task is to write a python program to join all the strings with maximum magnitudes.
Examples:
Input : test_list = [(“Gfg is best”, 8), (“gfg is good”, 7), (“for”, 2), (“for all geeks”, 8)]
Output : “Gfg is best for all geeks”
Explanation : 8 is maximum tuple element and concatenation of keys yield the result.
Input : test_list = [(“Gfg is best”, 7), (“gfg is good”, 8), (“for”, 2), (“for all geeks”, 8)]
Output : “gfg is good for all geeks”
Explanation : 8 is maximum tuple element and concatenation of keys yield the result.
Method #1 : Using max() + itemgetter() + list comprehension + join()
In this, we perform task of getting maximum magnitude numbers using max(), itemgetter handles the index to query. The strings are joined by join() after matching using list comprehension.
Python3
# Python3 code to demonstrate working of# Concatenate Maximum Tuples# Using max() + itemgetter() + list comprehension + join()from operator import itemgetter# initializing listtest_list = [("Gfg is best", 8), ("gfg is good", 7), ("for", 2), ("for all geeks", 8)]# printing original listprint("The original list is : " + str(test_list))# getting maximummax_ele = max(test_list, key=itemgetter(1))[1]# joining maximumres = ' '.join([key for key, ele in test_list if ele == max_ele])# printing resultprint("The maximum concatenated strings : " + str(res)) |
Output:
The original list is : [(‘Gfg is best’, 8), (‘gfg is good’, 7), (‘for’, 2), (‘for all geeks’, 8)]
The maximum concatenated strings : Gfg is best for all geeks
Method #2 : Using filter() + max() + itemgetter()
In this, we perform task of filtering using filter() rather than list comprehension. Rest all the functionalities is similar to all the method.
Python3
# Python3 code to demonstrate working of# Concatenate Maximum Tuples# Using filter() + max() + itemgetter()from operator import itemgetter# initializing listtest_list = [("Gfg is best", 8), ("gfg is good", 7), ("for", 2), ("for all geeks", 8)]# printing original listprint("The original list is : " + str(test_list))# getting maximummax_ele = max(test_list, key=itemgetter(1))[1]# joining maximum# filter checks for maximum values and concatsres = " ".join([ele[0] for ele in filter(lambda ele: ele[1] == max_ele, test_list)])# printing resultprint("The maximum concatenated strings : " + str(res)) |
Output:
The original list is : [(‘Gfg is best’, 8), (‘gfg is good’, 7), (‘for’, 2), (‘for all geeks’, 8)]
The maximum concatenated strings : Gfg is best for all geeks
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