Python – Check if Splits are equal

Given String separated by delim, check if all splits are similar.

Input : ’45#45#45′, delim = ‘#’ Output : True Explanation : All equal to 45. Input : ‘4@5@5’, delim = ‘@’ Output : False Explanation : 1st segment equal to 4, rest 5.

Method #1 : Using set() + len() + split()

In this, we perform split to get elements in list format, then convert to set, duplicates are removed, and check for len == 1, confirms all elements are same.

Python3

# Python3 code to demonstrate working of
# Check if Splits are equal
# Using set() + len() + split()

# initializing string
test_str = '45# 45# 45# 45# 45'

# printing original string
print("The original string is : " + str(test_str))

# initializing splt_chr
splt_chr = "#"

# checking for length of set obtained, res stores boolean result
res = len(list(set(test_str.split(splt_chr)))) == 1

# printing result
print("Are all splits equal ? : " + str(res))

Output

The original string is : 45#45#45#45#45
Are all splits equal ? : True

Time complexity: O(n), where n is the length of the test_list. The set() + len() + split() takes O(n) time
Auxiliary Space: O(1), extra constant space is required

Method #2 : Using split() + all()

In this, we perform task of checking for all elements equal using all().

Python3

# Python3 code to demonstrate working of
# Check if Splits are equal
# Using split() + all()

# initializing string
test_str = '45# 45# 45# 45# 45'

# printing original string
print("The original string is : " + str(test_str))

# initializing splt_chr
splt_chr = "#"

# splitting using split()
new_list = test_str.split(splt_chr)

# checking all equal to 1st element
res = all(ele == new_list[0] for ele in new_list)

# printing result
print("Are all splits equal ? : " + str(res))

Output

The original string is : 45#45#45#45#45
Are all splits equal ? : True