Python | Check if list contains consecutive numbers
Given a list of numbers, write a Python program to check if the list contains consecutive integers.
Examples:
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Input : [2, 3, 1, 4, 5] Output : True Input : [1, 2, 3, 5, 6] Output : False
Let’s discuss the few ways we can do this task.
Approach #1 : using sorted()
This approach uses sorted() function of Python. We compare the sorted list with list of range of minimum and maximum integer of the list and return it.
# Python3 Program to Create list # with integers within given range def checkConsecutive(l): return sorted(l) == list(range(min(l), max(l)+1)) # Driver Codelst = [2, 3, 1, 4, 5]print(checkConsecutive(lst)) |
True
Approach #2 : Using numpy.diff()
Numpy module provides a function diff() that calculate the n-th discrete difference along the given axis. We find the iterative difference of the sorted list and check if it is equal to 1.
# Python3 Program to Create list # with integers within given range import numpy as np def checkConsecutive(l): n = len(l) - 1 return (sum(np.diff(sorted(l)) == 1) >= n) # Driver Codelst = [2, 3, 1, 4, 5]print(checkConsecutive(lst)) |
True
