# Python – Check if Kth index elements are unique

Given a String list, check if all Kth index elements are unique.

Input : test_list = [“gfg”, “best”, “for”, “geeks”], K = 1
Output : False
Explanation : e occurs as 1st index in both best and geeks.

Input : test_list = [“gfg”, “best”, “geeks”], K = 2
Output : True
Explanation : g, s, e, all are unique.

Method #1 : Using loop

This is brute way to solve this problem. In this, we iterate for each string and flag off when any element is repeated, and return false.

## Python3

 `# Python3 code to demonstrate working of  ` `# Check if Kth index elements are unique ` `# Using loop ` ` `  `# initializing list ` `test_list ``=` `[``"gfg"``, ``"best"``, ``"for"``, ``"geeks"``]  ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# initializing K  ` `K ``=` `2` ` `  `res ``=` `[] ` `flag ``=` `True` `for` `ele ``in` `test_list: ` `     `  `    ``# checking if element is repeated ` `    ``if` `ele[K] ``in` `res: ` `        ``flag ``=` `False` `        ``break` `    ``else``: ` `        ``res.append(ele[K]) ` `         `  `# printing result  ` `print``(``"Is Kth index all unique : "` `+` `str``(flag))`

Output

```The original list is : ['gfg', 'best', 'for', 'geeks']
Is Kth index all unique : True

```

Method #2 : Using Counter() + all()

In this, we count frequency of each char. at Kth index, and all() is used to check if Counter is less than 2 for all.

## Python3

 `# Python3 code to demonstrate working of  ` `# Check if Kth index elements are unique ` `# Using Counter() + all() ` `from` `collections ``import` `Counter ` ` `  `# initializing list ` `test_list ``=` `[``"gfg"``, ``"best"``, ``"for"``, ``"geeks"``]  ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# initializing K  ` `K ``=` `2` ` `  `# getting count of each Kth index item ` `count ``=` `Counter(sub[K] ``for` `sub ``in` `test_list) ` ` `  `# extracting result  ` `res ``=` `all``(val < ``2` `for` `val ``in` `count.values()) ` `         `  `# printing result  ` `print``(``"Is Kth index all unique : "` `+` `str``(res))`

Output

```The original list is : ['gfg', 'best', 'for', 'geeks']
Is Kth index all unique : True

```

Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.

To begin with, your interview preparations Enhance your Data Structures concepts with the Python DS Course.

My Personal Notes arrow_drop_up Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.

Article Tags :

Be the First to upvote.

Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.