Python – Check if elements index are equal for list elements
Given two lists and check list, test if for each element in check list, elements occur in similar index in 2 lists.
Input : test_list1 = [2, 6, 9, 7, 8], test_list2 = [2, 7, 9, 4, 8], check_list = [9, 8, 7]
Output : False
Explanation : 7 is at 4th and 2nd place in both list, hence False.Input : test_list1 = [2, 6, 9, 7, 8], test_list2 = [2, 6, 9, 4, 8], check_list = [9, 8, 6]
Output : True
Explanation : All from checklist at similar index, hence True.
Method #1 : Using loop
In this, we iterate for all the elements in list, if elements are different and is present in check list, then False is returned.
Python3
# Python3 code to demonstrate working of # Check if elements index are equal for list elements# Using loop # initializing liststest_list1 = [2, 6, 9, 7, 8]test_list2 = [2, 7, 9, 4, 8] # printing original listsprint("The original list 1 : " + str(test_list1))print("The original list 2 : " + str(test_list2)) # initializing check_listcheck_list = [9, 8, 2] res = True for idx, ele in enumerate(test_list1): # check for indifference and containment if test_list1[idx] != test_list2[idx] and ele in check_list: res = False break # printing result print("Are elements at same index for required instances ?: " + str(res)) |
The original list 1 : [2, 6, 9, 7, 8] The original list 2 : [2, 7, 9, 4, 8] Are elements at same index for required instances ?: True
Method #2 : Using zip() + all() + generator expression
In this, we pair like indices using zip() and then all() is used to check for all indices, generator expression is used for iteration logic.
Python3
# Python3 code to demonstrate working of # Check if elements index are equal for list elements# Using zip() + all() + generator expression # initializing liststest_list1 = [2, 6, 9, 7, 8]test_list2 = [2, 7, 9, 4, 8] # printing original listsprint("The original list 1 : " + str(test_list1))print("The original list 2 : " + str(test_list2)) # initializing check_listcheck_list = [9, 8, 2] # checking for all elements equal in check list using all()res = all(a == b for a, b in zip(test_list1, test_list2) if a in check_list) # printing result print("Are elements at same index for required instances ?: " + str(res)) |
The original list 1 : [2, 6, 9, 7, 8] The original list 2 : [2, 7, 9, 4, 8] Are elements at same index for required instances ?: True
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