Python | Check if all elements in a List are same

Last Updated : 08 Dec, 2018

Given a list, write a Python program to check if all the elements in given list are same.

Example:

Input: ['Geeks', 'Geeks', 'Geeks', 'Geeks', ]
Output: Yes

Input: ['Geeks', 'Is', 'all', 'Same', ]
Output: No

There are various ways we can do this task. Let’s see different ways we can check if all elements in a List are same.

Method #1: Comparing each element.

# Python program to check if all  
# ments in a List are same  
  
def ckeckList(lst): 
  
    ele = lst[0] 
    chk = True
      
    # Comparing each element with first item  
    for item in lst: 
        if ele != item: 
            chk = False
            break; 
              
    if (chk == True): print("Equal") 
    else: print("Not equal")             
  
# Driver Code 
lst = ['Geeks', 'Geeks', 'Geeks', 'Geeks', ] 
ckeckList(lst) 

Output:

Equal

But In Python, we can do the same task in much interesting ways.

Method #2: Using all() method

# Python program to check if all  
# elements in a List are same  
res = False
  
def chkList(lst): 
    if len(lst) < 0 : 
        res = True
    res = all(ele == lst[0] for ele in lst) 
      
    if(res): 
        print("Equal") 
    else: 
        print("Not equal") 
  
# Driver Code         
lst = ['Geeks', 'Geeks', 'Geeks', 'Geeks'] 
chkList(lst) 

Output:

Equal

Method #3: Using count() method

# Python program to check if all  
# elements in a List are same  
res = False
  
def chkList(lst): 
    if len(lst) < 0 : 
        res = True
    res = lst.count(lst[0]) == len(lst) 
      
    if(res): 
        print("Equal") 
    else: 
        print("Not equal") 
  
# Driver Code         
lst = ['Geeks', 'Geeks', 'Geeks', 'Geeks'] 
chkList(lst) 

Output:

Equal

Method #4: Using set data structure
Since we know there cannot be duplicate elements in a set, we can use this property to check whether all the elements are same or not.

# Python program to check if all  
# elements in a List are same  
  
def chkList(lst): 
    return len(set(lst)) == 1
  
  
# Driver Code         
lst = ['Geeks', 'Geeks', 'Geeks', 'Geeks'] 
  
if chkList(lst) == True: print("Equal") 
else: print("Not Equal") 

Output:

Equal

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