Python | Check if a given string is binary string or not

Given a string str. The task is to check whether it is a binary string or not.

Examples: 

Input: str = "01010101010"
Output: Yes

Input: str = "geeks101"
Output: No

Approach 1: Using Set



  1. Insert the given string in a set
  2. Check if the set characters consist of 1 and/or 0 only.
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# Python program to check
# if a string is binary or not
  
# function for checking the
# string is accepted or not
def check(string) :
  
    # set function convert string
    # into set of characters .
    p = set(string)
  
    # declare set of '0', '1' .
    s = {'0', '1'}
  
    # check set p is same as set s
    # or set p contains only '0'
    # or set p contains only '1'
    # or not, if any one condition
    # is true then string is accepted
    # otherwise not .
    if s == p or p == {'0'} or p == {'1'}:
        print("Yes")
    else :
        print("No")
  
  
          
# driver code
if __name__ == "__main__" :
  
    string = "101010000111"
  
    # function calling
    check(string)

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Output:


Yes





Approach 2:  Simple Iteration


    

  1. Iterate for every character and check if the character is 0 or 1. 
    2. 

  2. If it is not then set a counter and break.
    3. 

  3.  After iteration check whether the counter is set or not.
    4. 












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# Python program to check 


# if a string is binary or not 


  


# function for checking the 


# string is accepted or not 


def check2(string) : 


  


    # initialize the variable t 


    # with '01' string 


    t = '01'


  


    # initialize the variable count 


    # with 0 value 


    count = 0


  


    # looping through each character 


    # of the string . 


    for char in string : 


  


        # check the character is present in 


        # string t or not. 


        # if this condition is true 


        # assign 1 to the count variable 


        # and break out of the for loop 


        # otherwise pass 


        if char not in t : 


            count = 1


            break


        else : 


            pass


          


    # after coming out of the loop 


    # check value of count is non-zero or not 


    # if the value is non-zero the en condition is true 


    # and string is not accepted 


    # otherwise string is accepted 


    if count : 


        print("No") 


    else : 


        print("Yes") 


  


  


  


# driver code 


if __name__ == "__main__" : 


  


    string = "001021010001010"


  


    # function calling 


    check2(string) 



















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Output:


No








    

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