Python | Check if a given object is list or not

Given an object, the task is to check whether the object is list or not. Method #1: Using isinstance

Python3

# Python code to demonstrate
# check whether the object
# is a list or not

# initialisation list
ini_list1 = [1, 2, 3, 4, 5]
ini_list2 = '12345'

# code to check whether
# object is a list or not
if isinstance(ini_list1, list):
  print("your object is a list !")
else:
    print("your object is not a list")

if isinstance(ini_list2, list):
    print("your object is a list")
else:
    print("your object is not a list")

Output:

your object is a list !
your object is not a list

Method #2: Using type(x)

Python3

# Python code to demonstrate
# check whether object
# is a list or not

# initialisation list
ini_list1 = [1, 2, 3, 4, 5]
ini_list2 = (12, 22, 33)

# code to check whether
# object is a list or not
if type(ini_list1) is list:
    print("your object is a list")
else:
    print("your object is not a list")

if type(ini_list2) is list:
    print("your object is a list")
else:
    print("your object is not a list")

Output:

your object is a list
your object is not a list

Method #3: Using __class__

To check if an object is a list , you can use the __class__ attribute and compare it to the list type:

Python3

# initializing list
ini_list1 = [1, 2, 3, 4, 5]
ini_list2 = (12, 22, 33)

# code to check whether object is a list or not
if ini_list1.__class__ == list:
    print("ini_list1 is a list")
else:
    print("ini_list1 is not a list")

if ini_list2.__class__ == list:
    print("ini_list2 is a list")
else:
    print("ini_list2 is not a list")
#This code is contributed by Edula Vinay Kumar Reddy

Output

ini_list1 is a list
ini_list2 is not a list