# Python – Check for Sublist in List

• Last Updated : 16 Feb, 2022

Sometimes, while working with Python Lists, we can have a problem in which we need to check if a particular sublist is contained in an exact sequence in a list. This task can have application in many domains such as school programming and web development. Let’s discuss certain ways in which this task can be performed.

Input : test_list = [5, 6, 3, 8, 2, 1, 7, 1], sublist = [8, 2, 3]
Output : False
Input : test_list = [5, 6, 3, 8, 2, 3, 7, 1], sublist = [8, 2, 3]
Output : True

Method #1 : Using loop + list slicing
The combination of the above functions can be used to solve this problem. In this, we perform the task of checking for sublist by incremental slicing using the list slicing technique.

## Python3

 `# Python3 code to demonstrate working of``# Check for Sublist in List``# Using loop + list slicing` `# initializing list``test_list ``=` `[``5``, ``6``, ``3``, ``8``, ``2``, ``1``, ``7``, ``1``]` `# printing original list``print``("The original ``list` `: " ``+` `str``(test_list))` `# initializing sublist``sublist ``=` `[``8``, ``2``, ``1``]` `# Check for Sublist in List``# Using loop + list slicing``res ``=` `False``for` `idx ``in` `range``(``len``(test_list) ``-` `len``(sublist) ``+` `1``):``        ``if` `test_list[idx : idx ``+` `len``(sublist)] ``=``=` `sublist:``            ``res ``=` `True``            ``break``        ` `# printing result``print``("Is sublist present ``in` `list` `? : " ``+` `str``(res))`

Output :

```The original list : [5, 6, 3, 8, 2, 1, 7, 1]
Is sublist present in list ? : True```

Method #2 : Using any() + list slicing + generator expression
The combination of the above functions is used to solve this problem. In this, we perform the task of checking for any sublist equating to desired using any(), and list slicing is used to slice incremental list of the desired length.

## Python3

 `# Python3 code to demonstrate working of``# Check for Sublist in List``# Using any() + list slicing + generator expression` `# initializing list``test_list ``=` `[``5``, ``6``, ``3``, ``8``, ``2``, ``1``, ``7``, ``1``]` `# printing original list``print``("The original ``list` `: " ``+` `str``(test_list))` `# initializing sublist``sublist ``=` `[``8``, ``2``, ``1``]` `# Check for Sublist in List``# Using any() + list slicing + generator expression``res ``=` `any``(test_list[idx : idx ``+` `len``(sublist)] ``=``=` `sublist``        ``for` `idx ``in` `range``(``len``(test_list) ``-` `len``(sublist) ``+` `1``))``        ` `# printing result``print``("Is sublist present ``in` `list` `? : " ``+` `str``(res))`

Output :

```The original list : [5, 6, 3, 8, 2, 1, 7, 1]
Is sublist present in list ? : True```

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