Given a list of elements extract the average digit count in List.
Input : test_list = [34, 2345, 23, 456, 2, 23, 456787]
Output : 2.857142857142857
Explanation : Average of all digit count. [2+4+2+3+1+2+6 = 20, 20/7 = 2.857142857142857]Input : test_list = [34, 1, 456]
Output : 2.0
Explanation : Average of all digit count. [1 + 2 + 3 = 6, 6 / 3 = 2]
Method #1 : Using len() + loop + str()
In this, we iterate each element, convert to string, and find its length, perform summation using counter, and then divide the result with the total element in the list to get results.
Python3
# Python3 code to demonstrate working of # Average digits count # Using len() + loop + str() # initializing list test_list = [34, 2345, 23, 456, 2, 23, 456787] # printing original list print("The original list is : " + str(test_list)) sumd = 0for ele in test_list: # summing digits length sumd += len(str(ele)) # getting result after dividing total digits by elements res = sumd / len(test_list) # printing result print("Average digits length : " + str(res)) |
The original list is : [34, 2345, 23, 456, 2, 23, 456787] Average digits length : 2.857142857142857
Method #2 : Using len() + sum() + str()
In this, the task of getting a sum is done using sum(), extends a compact way to solve the problem.
Python3
# Python3 code to demonstrate working of # Average digits count # Using len() + sum() + str() # initializing list test_list = [34, 2345, 23, 456, 2, 23, 456787] # printing original list print("The original list is : " + str(test_list)) # getting summation and dividing by total length res = sum([len(str(ele)) for ele in test_list]) / len(test_list) # printing result print("Average digits length " + str(res)) |
The original list is : [34, 2345, 23, 456, 2, 23, 456787] Average digits length 2.857142857142857
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