Python – Average digits count in a List

Given a list of elements extract the average digit count in List.

Input : test_list = [34, 2345, 23, 456, 2, 23, 456787] 
Output : 2.857142857142857 
Explanation : Average of all digit count. [2+4+2+3+1+2+6 = 20, 20/7 = 2.857142857142857]

Input : test_list = [34, 1, 456]
Output : 2.0 
Explanation : Average of all digit count. [1 + 2 + 3 = 6, 6 / 3 = 2] 

Method #1 : Using len() + loop + str()

In this, we iterate each element, convert to string, and find its length, perform summation using counter, and then divide the result with the total element in the list to get results.

Python3

# Python3 code to demonstrate working of
# Average digits count
# Using len() + loop + str()

# initializing list
test_list = [34, 2345, 23, 456, 2, 23, 456787]

# printing original list
print("The original list is : " + str(test_list))

sumd = 0
for ele in test_list:

    # summing digits length
    sumd += len(str(ele))

# getting result after dividing total digits by elements
res = sumd / len(test_list)

# printing result
print("Average digits length : " + str(res))

Output

The original list is : [34, 2345, 23, 456, 2, 23, 456787]
Average digits length : 2.857142857142857

Method #2 : Using len() + sum() + str()

In this, the task of getting a sum is done using sum(), extends a compact way to solve the problem.

Python3

# Python3 code to demonstrate working of
# Average digits count
# Using len() + sum() + str()

# initializing list
test_list = [34, 2345, 23, 456, 2, 23, 456787]

# printing original list
print("The original list is : " + str(test_list))

# getting summation and dividing by total length
res = sum([len(str(ele)) for ele in test_list]) / len(test_list)

# printing result
print("Average digits length " + str(res))

Output

The original list is : [34, 2345, 23, 456, 2, 23, 456787]
Average digits length 2.857142857142857