Python - Average digits count in a List

Python – Average digits count in a List

Last Updated : 11 Oct, 2020

Given a list of elements extract the average digit count in List.

Input : test_list = [34, 2345, 23, 456, 2, 23, 456787]
Output : 2.857142857142857
Explanation : Average of all digit count. [2+4+2+3+1+2+6 = 20, 20/7 = 2.857142857142857]
Input : test_list = [34, 1, 456]
Output : 2.0
Explanation : Average of all digit count. [1 + 2 + 3 = 6, 6 / 3 = 2]

Method #1 : Using len() + loop + str()

In this, we iterate each element, convert to string, and find its length, perform summation using counter, and then divide the result with the total element in the list to get results.

Python3

# Python3 code to demonstrate working of 
# Average digits count
# Using len() + loop + str()
  
# initializing list
test_list = [34, 2345, 23, 456, 2, 23, 456787]
  
# printing original list
print("The original list is : " + str(test_list))
  
sumd = 0
for ele in test_list:
      
    # summing digits length 
    sumd += len(str(ele))
  
# getting result after dividing total digits by elements    
res = sumd / len(test_list)
  
# printing result 
print("Average digits length : " + str(res))

Output

The original list is : [34, 2345, 23, 456, 2, 23, 456787]
Average digits length : 2.857142857142857

Method #2 : Using len() + sum() + str()

In this, the task of getting a sum is done using sum(), extends a compact way to solve the problem.

Python3

# Python3 code to demonstrate working of 
# Average digits count
# Using len() + sum() + str()
  
# initializing list
test_list = [34, 2345, 23, 456, 2, 23, 456787]
  
# printing original list
print("The original list is : " + str(test_list))
  
# getting summation and dividing by total length
res = sum([len(str(ele)) for ele in test_list]) / len(test_list)
  
# printing result 
print("Average digits length " + str(res))

Output

The original list is : [34, 2345, 23, 456, 2, 23, 456787]
Average digits length 2.857142857142857

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