# Python – Assign Frequency to Tuples

• Last Updated : 08 Aug, 2022

Given tuple list, assign frequency to each tuple in list.

Input : test_list = [(6, 5, 8), (2, 7), (6, 5, 8), (9, ), (2, 7)]
Output : [(6, 5, 8, 2), (2, 7, 2), (9, 1)]
Explanation : (2, 7) occurs 2 times, hence 2 is append in tuple.
Input : test_list = [(2, 7), (2, 7), (6, 5, 8), (9, ), (2, 7)]
Output : [(6, 5, 8, 1), (2, 7, 3), (9, 1)]
Explanation : (2, 7) occurs 3 times, hence 3 is append in tuple.

Method #1 : Using Counter() + items() + * operator + list comprehension

In this, we extract the frequency using Counter(), fetch frequency numbers using items(), * operator is used to unpack elements and list comprehension is used to assign this to all elements in tuple list.

## Python3

 `# Python3 code to demonstrate working of``# Assign Frequency to Tuples``# Using Counter() + items() + * operator + list comprehension``from` `collections ``import` `Counter` `# initializing list``test_list ``=` `[(``6``, ``5``, ``8``), (``2``, ``7``), (``6``, ``5``, ``8``), (``6``, ``5``, ``8``), (``9``, ), (``2``, ``7``)]` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))` `# one-liner to solve problem``# assign Frequency as last element of tuple``res ``=` `[(``*``key, val) ``for` `key, val ``in` `Counter(test_list).items()]` `# printing results``print``(``"Frequency Tuple list : "` `+` `str``(res))`

Output

```The original list is : [(6, 5, 8), (2, 7), (6, 5, 8), (6, 5, 8), (9, ), (2, 7)]
Frequency Tuple list : [(6, 5, 8, 3), (2, 7, 2), (9, 1)]```

Method #2 : Using most_common() + Counter() + * operator + list comprehension

This is similar to the above method, just most_common() performs sort operation on list, which is not necessary.

## Python3

 `# Python3 code to demonstrate working of``# Assign Frequency to Tuples``# Using most_common() + Counter() + * operator + list comprehension``from` `collections ``import` `Counter` `# initializing list``test_list ``=` `[(``6``, ``5``, ``8``), (``2``, ``7``), (``6``, ``5``, ``8``), (``6``, ``5``, ``8``), (``9``, ), (``2``, ``7``)]` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))` `# most_common performs sort on arg. list``# assign Frequency as last element of tuple``res ``=` `[(``*``key, val) ``for` `key, val ``in` `Counter(test_list).most_common()]` `# printing results``print``(``"Frequency Tuple list : "` `+` `str``(res))`

Output

```The original list is : [(6, 5, 8), (2, 7), (6, 5, 8), (6, 5, 8), (9, ), (2, 7)]
Frequency Tuple list : [(6, 5, 8, 3), (2, 7, 2), (9, 1)]```

Method #3 : Using count(),list(),tuple() methods

## Python3

 `# Python3 code to demonstrate working of``# Assign Frequency to Tuples` `# initializing list``test_list ``=` `[(``6``, ``5``, ``8``), (``2``, ``7``), (``6``, ``5``, ``8``), (``6``, ``5``, ``8``), (``9``, ), (``2``, ``7``)]` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))` `# one-liner to solve problem``# assign Frequency as last element of tuple``res``=``[]``for` `i ``in` `test_list:``    ``if` `i ``not` `in` `res:``        ``res.append(i)``res1``=``[]``for` `i ``in` `res:``    ``x``=``list``(i)``    ``x.append(test_list.count(i))``    ``p``=``tuple``(x)``    ``res1.append(p)` `# printing results``print``(``"Frequency Tuple list : "` `+` `str``(res1))`

Output

```The original list is : [(6, 5, 8), (2, 7), (6, 5, 8), (6, 5, 8), (9,), (2, 7)]
Frequency Tuple list : [(6, 5, 8, 3), (2, 7, 2), (9, 1)]```

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