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Python | Arrange Tuples consecutively in list
• Last Updated : 05 Sep, 2019

Sometimes, while working with tuple list, we may require a case in which we require that a tuple starts from the end of previous tuple, i.e the element 0 of every tuple should be equal to ending element of tuple in list of tuple. This type of problem and sorting is useful in competitive programming. Let’s discuss way in which this problem can be solved.

Method : Using loop + `dict()`
This task can easily be solved by converting a tuple container list to dictionary and then it’s easy to access a value of a key and arrange them accordingly to sort in a way in which one tuple element begins with the ending of other element.

 `# Python3 code to demonstrate working of ` `# Arranging Tuples consecutively in list ` `# using loop + dict() ` ` `  `# initialize list ` `test_list ``=` `[(``5``, ``6``), (``11``, ``8``), (``6``, ``11``), (``8``, ``9``) ] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# Arranging Tuples consecutively in list ` `# using loop + dict() ` `temp ``=` `dict``(test_list)   ` `ele ``=` `test_list[``0``][``0``]   ` `res ``=` `[]  ` `for` `_ ``in` `range``(``len``(test_list)): ` `    ``res.append((ele, temp[ele])) ` `    ``ele ``=` `temp[ele] ` ` `  `# printing result ` `print``(``"The arranged list is : "` `+` `str``(res)) `

Output :

```The original list is : [(5, 6), (11, 8), (6, 11), (8, 9)]
The arranged list is : [(5, 6), (6, 11), (11, 8), (8, 9)]
```

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