Being familiar with the concept of queue, which follows FIFO rule, i.e first in first out, that suggests a front removal and rear insertion. This has been discussed many times. But sometimes we need to perform the exact opposite of this and we need to perform the append at front and remove element from the rear. Let’s discuss certain ways in which this can be done.
Method #1 : Using + operator and list slicing
These operators can be used to perform this particular task. The append operation can be done with the help of + operator and the removal of rear can be done using the conventional list slicing.
# Python3 code to demonstrate # append from front and remove from rear # using + operator and list slicing # initializing list test_list = [4, 5, 7, 3, 10] # printing original list print("The original list : " + str(test_list)) # using + operator and list slicing # append from front and remove from rear res = [13] + test_list[:-1] # printing result print("The list after append and removal : " + str(res)) |
The original list : [4, 5, 7, 3, 10] The list after append and removal : [13, 4, 5, 7, 3]
Method #2 : Using collections.deque()
The doubly ended queue can be used to perform this particular task in which is supported by python using the collection library, the appendleft and pop methods of queue function can be used to perform this job.
# Python3 code to demonstrate # append from front and remove from rear # using collections.deque from collections import deque # initializing list test_list = [4, 5, 7, 3, 10] # printing original list print("The original list : " + str(test_list)) # using collections.deque # append from front and remove from rear res = deque(test_list) res.appendleft(13) res.pop() res = list(res) # printing result print("The list after append and removal : " + str(res)) |
The original list : [4, 5, 7, 3, 10] The list after append and removal : [13, 4, 5, 7, 3]
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