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Python | Accumulative index summation in tuple list
• Last Updated : 21 Nov, 2019

Sometimes, while working with data, we can have a problem in which we need to find accumulative summation of each index in tuples. This problem can have application in web development and competitive programming domain. Let’s discuss certain way in which this problem can be solved.

Method : Using `accumulate() + sum() + lambda + map() + tuple() + zip()`
The combination of above functions can be used to solve this task. In this, we pair the elements using `zip()`, the then we perform the sum of them and we extend this to all elements using `map()`. The taking forward of sum is done by using accumulate. The binding of all logic is done by lambda function.

 `# Python3 code to demonstrate working of``# Accumulative index summation in tuple list``# Using accumulate() + sum() + lambda + map() + tuple() + zip()``from` `itertools ``import` `accumulate`` ` `# initialize list``test_list ``=` `[(``3``, ``4``, ``5``), (``4``, ``5``, ``7``), (``1``, ``4``, ``10``)]`` ` `# printing original list ``print``(``"The original list : "` `+` `str``(test_list))`` ` `# Accumulative index summation in tuple list``# Using accumulate() + sum() + lambda + map() + tuple() + zip()``res ``=` `list``(accumulate(test_list, ``lambda` `i, j: ``tuple``(``map``(``sum``, ``zip``(i, j)))))`` ` `# printing result``print``(``"Accumulative index summation of tuple list : "` `+` `str``(res))`
Output :
```The original list : [(3, 4, 5), (4, 5, 7), (1, 4, 10)]
Accumulative index summation of tuple list : [(3, 4, 5), (7, 9, 12), (8, 13, 22)]
```

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