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PyQt5 QSpinBox – Finding child using child type

Last Updated : 10 Feb, 2023
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In this article we will see how we can find the child of spin box using the child type, child type is the quality of child for example push button type is QPushButton. Spin box is made of two child one is line edit whose type is QLineEdit and other is the up and down button whose type are QValidator.

In order to do this we use findChild method 

Syntax : spin_box.findChild(child_type) 

Argument : It takes child type as argument 

Return : It returns the child object, if no child is found it return None

Below is the implementation 

Python3




# importing libraries
from PyQt5.QtWidgets import *
from PyQt5 import QtCore, QtGui
from PyQt5.QtGui import *
from PyQt5.QtCore import *
import sys
 
 
class Window(QMainWindow):
 
    def __init__(self):
        super().__init__()
 
        # setting title
        self.setWindowTitle("Python ")
 
        # setting geometry
        self.setGeometry(100, 100, 600, 400)
 
        # calling method
        self.UiComponents()
 
        # showing all the widgets
        self.show()
 
        # method for widgets
    def UiComponents(self):
        # creating spin box
        self.spin = QSpinBox(self)
 
        # setting geometry to spin box
        self.spin.setGeometry(100, 100, 250, 40)
 
        # setting range to the spin box
        self.spin.setRange(0, 999999)
 
        # setting prefix to spin
        self.spin.setPrefix("Prefix ")
 
        # setting suffix to spin
        self.spin.setSuffix(" Suffix")
 
 
        # getting child using child type
        child = self.spin.findChild(QLineEdit)
 
        # creating a label
        label = QLabel(self)
 
        # making it multi line
        label.setWordWrap(True)
 
        # setting its geometry
        label.setGeometry(100, 200, 200, 60)
 
        # setting text to the label
        label.setText(str(child))
 
 
 
# create pyqt5 app
App = QApplication(sys.argv)
 
# create the instance of our Window
window = Window()
 
# start the app
sys.exit(App.exec())


Output :

 



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