Open In App

PyQt5 – Checking if label is multi line or not

Improve
Improve
Like Article
Like
Save
Share
Report

In this article we will see how we can check if label is multi-line or not, when we create a label and set text to it and if the text length is greater then the length of the label extra text did not show, multi line label make that extra text go into the other line. Below is the representation of how normal and multi line label looks like

   

In order to check if label is multi line or not we use wordWrap method.

Syntax : label.ordwWrap() Argument : It no argument Return : It returns bool

Below is the implementation 

Python3




# importing libraries
from PyQt5.QtWidgets import *
from PyQt5 import QtCore, QtGui
from PyQt5.QtGui import *
from PyQt5.QtCore import *
import sys
 
 
class Window(QMainWindow):
 
    def __init__(self):
        super().__init__()
 
        # setting title
        self.setWindowTitle("Python ")
 
        # setting geometry
        self.setGeometry(100, 100, 600, 400)
 
        # calling method
        self.UiComponents()
 
        # showing all the widgets
        self.show()
 
    # method for widgets
    def UiComponents(self):
        # creating label
        label1 = QLabel(self)
 
        # setting geometry to the label
        label1.setGeometry(200, 150, 100, 50)
 
        # adding border to the label
        label1.setStyleSheet("border : 2px solid black;")
 
        # creating label
        label2 = QLabel("Multi label i.e With multi line", self)
 
        # setting geometry to the label
        label2.setGeometry(200, 250, 100, 50)
 
        # adding border to the label
        label2.setStyleSheet("border : 2px solid black;")
 
        # making it multi line
        label2.setWordWrap(True)
 
        # check
        check = label2.wordWrap()
 
        # checking if label2 is multi line or not
        if check:
            label1.setText("YESSS")
 
        else:
            label1.setText("NOO")
 
 
# create pyqt5 app
App = QApplication(sys.argv)
 
# create the instance of our Window
window = Window()
 
window.show()
 
# start the app
sys.exit(App.exec())


Output :

 



Last Updated : 13 Jul, 2022
Like Article
Save Article
Previous
Next
Share your thoughts in the comments
Similar Reads