PYGLET – Loading Plain Text Document

In this article, we will see how we can load a plain text file in PYGLET module in python. Pyglet is easy to use but powerful library for developing visually rich GUI applications like games, multimedia, etc. A window is a “heavyweight” object occupying operating system resources. Windows may appear as floating regions or can be set to fill an entire screen (fullscreen). In order to load a file i.e resource we use resource module of pyglet. This module allows applications to specify a search path for resources. Relative paths are taken to be relative to the application’s __main__ module. Plain-text, or Plaintext is any text, text file, or document that contains only text. Unlike a rich-text document, a plain text file cannot have bold text, fonts, larger font sizes, or any other special text formatting. The picture is a visual example of plain text vs. formatted text

We can create a window object with the help of the command given below 

# creating a window
window = pyglet.window.Window(width, height, title)

In order to do this we use text method with the pyglet.resource
Syntax : resource.text(file_name)
Argument : It takes string i.e file name as argument
Return : It returns UnformattedDocument object 

Below is the implementation  

Python3

# importing pyglet module
import pyglet
import pyglet.window.key as key

# width of window
width = 500

# height of window
height = 500

# caption i.e title of the window
title = "Geeksforgeeks"

# creating a window
window = pyglet.window.Window(width, height, title)

# text
text = "Welcome to GeeksforGeeks"

# creating label with following properties
# font = cooper
# position = 250, 150
# anchor position = center
label = pyglet.text.Label(text,
                          font_name ='Cooper',
                          font_size = 16,
                          x = 250,
                          y = 150,
                          anchor_x ='center',
                          anchor_y ='center')


# creating a batch
batch = pyglet.graphics.Batch()

# loading geeksforgeeks image
image = pyglet.image.load('gfg.png')


# creating sprite object
# it is instance of an image displayed on-screen
sprite = pyglet.sprite.Sprite(image, x = 200, y = 230)

# on draw event
@window.event
def on_draw():

    # clear the window
    window.clear()

    # draw the label
    label.draw()

    # draw the image on screen
    sprite.draw()

# key press event
@window.event
def on_key_press(symbol, modifier):

    # key "C" get press
    if symbol == key.C:

        # printing the message
        print("Key : C is pressed")

# image for icon
img = image = pyglet.resource.image("gfg.png")

# setting image as icon
window.set_icon(img)


# loading a plain text file
value = pyglet.resource.text("plain.txt")

# setting text  of label
label.text = str(value)

# start running the application
pyglet.app.run()

Output :