PYGLET – Getting Program Entry Directory

In this article we will see how we can get the program entry directory in PYGLET module in python. Pyglet is easy to use but powerful library for developing visually rich GUI applications like games, multimedia etc. A window is a “heavyweight” object occupying operating system resources. Windows may appear as floating regions or can be set to fill an entire screen (fullscreen). In order to load a file i.e resource we use resource module of pyglet. This module allows applications to specify a search path for resources. Relative paths are taken to be relative to the application’s __main__ module. For ordinary Python scripts, this is the directory containing the __main__ module. For executables created with py2exe the result is the directory containing the running executable file. For OS X bundles created using Py2App the result is the Resources directory within the running bundle.
We can create a window object with the help of command given below 

# creating a window
window = pyglet.window.Window(width, height, title)

In order to do this we use get_script_home method with the pyglet.resource
Syntax : resource.get_script_home()
Argument : It takes no argument
Return : It returns string 

Example: Below is the implementation :

Python3

porting pyglet module
import pyglet
import pyglet.window.key as key

# width of window
width = 500

# height of window
height = 500

# caption i.e title of the window
title = "Geeksforgeeks"

# creating a window
window = pyglet.window.Window(width, height, title)

# text
text = "Welcome to GeeksforGeeks"

# creating label with following properties
# font = cooper
# position = 250, 150
# anchor position = center
label = pyglet.text.Label(text,
                          font_name ='Cooper',
                          font_size = 16,
                          x = 250,
                          y = 150,
                          anchor_x ='center',
                          anchor_y ='center')


# creating a batch
batch = pyglet.graphics.Batch()

# loading geeksforgeeks image
image = pyglet.image.load('gfg.png')


# creating sprite object
# it is instance of an image displayed on-screen
sprite = pyglet.sprite.Sprite(image, x = 200, y = 230)

# on draw event
@window.event
def on_draw():

    # clear the window
    window.clear()

    # draw the label
    label.draw()

    # draw the image on screen
    sprite.draw()

# key press event
@window.event
def on_key_press(symbol, modifier):

    # key "C" get press
    if symbol == key.C:

        # printing the message
        print("Key : C is pressed")

# image for icon
img = image = pyglet.resource.image("gfg.png")

# setting image as icon
window.set_icon(img)


# getting directory containing the program entry
value = pyglet.resource.get_script_home()

# setting text  of label
label.text = str(value)

# start running the application
pyglet.app.run()

Output :