PYGLET – Getting Position on Line in Incremental Text Layout

In this article we will see how we can get the position on line in incremental text layout object in PYGLET module in python. Pyglet is easy to use but powerful library for developing visually rich GUI applications like games, multimedia etc. A window is a “heavyweight” object occupying operating system resources. Windows may appear as floating regions or can be set to fill an entire screen (fullscreen). Incremental text layout displays text which is suitable for interactive editing and/or scrolling large documents. Unlike TextLayout and ScrollableTextLayout, this class generates vertex lists only for lines of text that are visible. As the document is scrolled, vertex lists are deleted and created as appropriate to keep video memory usage to a minimum and improve rendering speed. Position is the closest document position for a given line index and X coordinate.

We can create a window and incremental text layout with the help of commands given below

# creating a window
window = pyglet.window.Window(width, height, title)

# creating a in
layout = pyglet.text.layout.IncrementalTextLayout(document, width, height)

In order to create window we use get_position_on_line method

Syntax : layout.get_position_on_line(line, x)

Argument : It takes two integer as argument



Return : It returns integer

Below is the implementation

filter_none

edit
close

play_arrow

link
brightness_4
code

# importing pyglet module
import pyglet
import pyglet.window.key
   
# width of window
width = 500
   
# height of window
height = 500
   
# caption i.e title of the window
title = "Geeksforgeeks"
   
# creating a window
window = pyglet.window.Window(width, height, title)
   
# text 
text = "GeeksforGeeks Learn and Grow, Portal for Geeks"
   
# batch object
batch = pyglet.graphics.Batch()
   
# creating a formatted document
# unlike unformatted document it is formatted
document = pyglet.text.document.FormattedDocument(text)
   
# setting style to the document
document.set_style(0, len(document.text), dict(font_name ='Arial', font_size = 16, color =(255, 255, 255, 255)))
   
# creating a incremental text layout
layout = pyglet.text.layout.IncrementalTextLayout(document, 400, 350, multiline = True, batch = batch)
   
# creating a caret
caret = pyglet.text.caret.Caret(layout, color =(150, 255, 150))
   
   
   
# caret to winow push handlers
window.push_handlers(caret)
   
# setting caret style
caret.set_style(dict(font_name ="Arial"))
   
# on draw event
@window.event
def on_draw():
       
    # clear the window
    window.clear()
       
    # draw the batch
    batch.draw()
       
    # caret to winow push handlers
    window.push_handlers(caret)
   
       
# key press event    
@window.event
def on_key_press(symbol, modifier):
   
    # key "C" get press
    if symbol == pyglet.window.key.C:
           
        # closing the window
        # window.close()
        pass
      
# image for icon
img = pyglet.resource.image("gfg.png")
  
# setting image as icon
window.set_icon(img)
  
# getting position on line
# line 0 and x = 100
value = layout.get_position_on_line(0, 100)
  
# printing value
print("Position on Line : ", end ="")
print(value)
   
# start running the application
pyglet.app.run()

chevron_right


Output :

Position on Line : 9

Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.

To begin with, your interview preparations Enhance your Data Structures concepts with the Python DS Course.




My Personal Notes arrow_drop_up

Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.


Article Tags :

Be the First to upvote.


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.