Puzzle | Marriage Party
3 types of people go to a marriage party.
Type 1 people : 1 man eats in 4 plates.
Type 2 people : 1 man eats in 2 plates.
Type 3 people : 4 men eat in 1 plate.
You are given that exactly 100 people go to the party and there are exactly 100 plates. So you have to calculate how many people of type 1, type 2 and type 3 will go to the party. Whereby the condition is all the 100 plates should be consumed by 100 people. And no plate will remaining after the party.
Let no. of plates consumed by people of type 1 are x, type 2 are y, and type 3 are z.
=> x + y + z = 100 ….(1)
So no. of plates consumed by type 1 are 4x, type 2 are 2y, and type 3 are z.
=> x/4 + y/2 + 4z = 100 ….(2)
( x will be the multiple of 4 and y will be the multiple of 2 because the no. of plates will be an Integer value)
By solving these two equations we get :-
=> 14z – x = 200 ….(3)
Now you have to manually find all value of x, and z from eq.(3) by considering their conditions
1) 15 < = z <= 24 (because eq.(3)) minimum no. of z will be 15 because if we take 14 then eq(3) will not satisfied, and maximum no. of z will be 24 because if we take 24 plates then 96 people and if take 25 plates then 100 people which is not possible because type 1 and type 2 are also exist there and z belongs to I.
2) 1 <= x <= 97 and will be the multiple of 4, x belongs to I.
3) 1 <= y <= 95 and will be the multiple of 2, y belongs to I.
And put the value of x, z in eq(1) and find y. If condition satisfied then it will be our final result.
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