GeeksforGeeks App
Open App
Browser
Continue

# Programs for printing pyramid patterns in Python

Patterns can be printed in python using simple for loops. First outer loop is used to handle the number of rows and the Inner nested loop is used to handle the number of columns. Manipulating the print statements, different number patterns, alphabet patterns, or star patterns can be printed.

• Simple pyramid pattern

## Python3

 # Python 3.x code to demonstrate star pattern # Function to demonstrate printing patterndef pypart(n):         # outer loop to handle number of rows    # n in this case    for i in range(0, n):             # inner loop to handle number of columns        # values changing acc. to outer loop        for j in range(0, i+1):                     # printing stars            print("* ",end="")              # ending line after each row        print("\r") # Driver Coden = 5pypart(n)

Output

*
* *
* * *
* * * *
* * * * *

Time Complexity: O(n2),This algorithm has a time complexity of O(n2). This is because the outer loop runs n times and the inner loop runs n times for each iteration of the outer loop, resulting in a total of n2 iterations.

Space Complexity: O(1),This algorithm has a space complexity of O(1). This is because there are no auxiliary data structures (such as arrays or lists) used, only primitives and constants.

Approach 2: Using List in Python 3, this could be done in a simpler way

## Python

 # Python 3.x code to demonstrate star pattern # Function to demonstrate printing patterndef pypart(n):    myList = []    for i in range(1,n+1):        myList.append("*"*i)    print("\n".join(myList)) # Driver Coden = 5pypart(n)

Output

*
**
***
****
*****

Time Complexity: O(n) ,The time complexity of this code is O(n), as it iterates through a loop of size n, where n is the number of stars to be printed.

Space Complexity: O(n) ,The space complexity of this code is O(n), as the myList array is used to store the string of stars, which is of size n.

Approach 3: Using recursion

## Python3

 #python3 code to print pyramid pattern using recursiondef pypart(n):    if n==0:        return    else:        pypart(n-1)        print("* "*n)  # Driver Coden = 5pypart(n)#this code is contributed by Shivesh Kumar Dwivedi

Output

*
* *
* * *
* * * *
* * * * *

Approach 4: Using while loop

## Python3

 # python3 code to print pyramid pattern using while loop # inputn=5 i=1;j=0# while loop check the condition until the# condition become false. if it is true then# enter in to loop and print the patternwhile(i<=n):    while(j<=i-1):        print("* ",end="")        j+=1     # printing next line for each row    print("\r")    j=0;i+=1            # this code is contributed by gangarajula laxmi

Output

*
* *
* * *
* * * *
* * * * *

The time complexity of the given code is O(n^2), where n is the input size.

Space complexity is O(1).

• After 180 degrees rotation

## Python3

 # Python 3.x code to demonstrate star pattern # Function to demonstrate printing patterndef pypart2(n):         # number of spaces    k = 2*n - 2     # outer loop to handle number of rows    for i in range(0, n):             # inner loop to handle number spaces        # values changing acc. to requirement        for j in range(0, k):            print(end=" ")             # decrementing k after each loop        k = k - 2             # inner loop to handle number of columns        # values changing acc. to outer loop        for j in range(0, i+1):                     # printing stars            print("* ", end="")             # ending line after each row        print("\r") # Driver Coden = 5pypart2(n)

Output

*
* *
* * *
* * * *
* * * * *

Optimized Solution:

Here, we have to print a space (height – row) times and then print “*” row times.

For example: let height of the pyramid is 5

then , on the row number 1 we print blank space 4 times(that is 5-1 or height -row)

and then we print star 1 time(that is row times) and then a new line

then , on the row number 2 we print blank space 3 times(that is 5-2 or height -row)

and then we print star 2 times (that is row times) and then a new line

and so on….

## Python3

 # python3 code to print pyramid pattern using while loopn=5;i=0while(i<=n):  print(" " * (n - i) +"*" * i)  i+=1

Output

*
**
***
****
*****

## Python3

 #python3 code to implement above approachheight = 5for row in range(1, height+ 1):    print(" " * (height - row) +"*" * row)#this code is contributed by Shivesh kumar dwivedi

Output

*
**
***
****
*****
• Printing Triangle

## Python3

 # Python 3.x code to demonstrate star pattern # Function to demonstrate printing pattern triangledef triangle(n):         # number of spaces    k = n - 1     # outer loop to handle number of rows    for i in range(0, n):             # inner loop to handle number spaces        # values changing acc. to requirement        for j in range(0, k):            print(end=" ")             # decrementing k after each loop        k = k - 1             # inner loop to handle number of columns        # values changing acc. to outer loop        for j in range(0, i+1):                     # printing stars            print("* ", end="")             # ending line after each row        print("\r") # Driver Coden = 5triangle(n)

Output

*
* *
* * *
* * * *
* * * * *
• Number Pattern

## Python3

 # Python 3.x code to demonstrate star pattern # Function to demonstrate printing pattern of numbersdef numpat(n):         # initialising starting number    num = 1     # outer loop to handle number of rows    for i in range(0, n):             # re assigning num        num = 1             # inner loop to handle number of columns            # values changing acc. to outer loop        for j in range(0, i+1):                         # printing number            print(num, end=" ")                     # incrementing number at each column            num = num + 1             # ending line after each row        print("\r") # Driver coden = 5numpat(n)

Output

1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
• Numbers without reassigning

## Python3

 # Python 3.x code to demonstrate star pattern # Function to demonstrate printing pattern of numbersdef contnum(n):         # initializing starting number    num = 1     # outer loop to handle number of rows    for i in range(0, n):             # not re assigning num        # num = 1             # inner loop to handle number of columns        # values changing acc. to outer loop        for j in range(0, i+1):                     # printing number            print(num, end=" ")                     # incrementing number at each column            num = num + 1             # ending line after each row        print("\r") n = 5 # sending 5 as argument# calling Functioncontnum(n)

Output

1
2 3
4 5 6
7 8 9 10
11 12 13 14 15
• Character Pattern

## Python3

 # Python 3.x code to demonstrate star pattern # Function to demonstrate printing pattern of alphabetsdef alphapat(n):         # initializing value corresponding to 'A'    # ASCII value    num = 65     # outer loop to handle number of rows    # 5 in this case    for i in range(0, n):             # inner loop to handle number of columns        # values changing acc. to outer loop        for j in range(0, i+1):                     # explicitly converting to char            ch = chr(num)                     # printing char value            print(ch, end=" ")             # incrementing number        num = num + 1             # ending line after each row        print("\r") # Driver Coden = 5alphapat(n)

Output

A
B B
C C C
D D D D
E E E E E
• Continuous Character pattern

## Python3

 # Python code 3.x to demonstrate star pattern # Function to demonstrate printing pattern of alphabets  def contalpha(n):     # initializing value corresponding to 'A'    # ASCII value    num = 65      # outer loop to handle number of rows- for i in range(0, n):     # inner loop to handle number of columns    # values changing acc. to outer loop    for j in range(0, i+1):         # explicitly converting to char        ch = chr(num)         # printing char value        print(ch, end=" ")         # incrementing at each column        num = num + 1     # ending line after each row    print("\r") # Driver coden = 5contalpha(n)

Output:

A
B C
D E F
G H I J
K L M N O

This article is contributed by Manjeet Singh(S.Nupur). If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.