Program to print window pattern

Print the pattern in which there is a hollow square and plus sign inside it. Pattern will be as per the n i.e. number of rows given as shown in example.

Examples:

Input : 6
Output : * * * * * *
         *   * *   * 
         * * * * * * 
         * * * * * * 
         *   * *   * 
         * * * * * *

Input : 7
Output : * * * * * * * 
         *     *     * 
         *     *     * 
         * * * * * * * 
         *     *     * 
         *     *     * 
         * * * * * * *

Approach:

We will start a for loop up till n and inside this also there is for loop up till n.
In this simply we have to check if row is first or last or column is first or last, then print “*”.
Now we have to check for the middle row and column.
So when n is odd, we will have a middle row and column and if row or column is in middle then we will print “*”.
If n is even,then rows or columns if equal to these values n/2 and (n/2)+1, then we will print “*”.
Else everywhere we have to print ” “(space).

Below is the implementation.

Python3

# Python program to print the pattern  
# hollow square with plus inside it 
# window pattern 
  
  
# function to print pattern n means  
# number of rows which we want 
def window_pattern(n): 
      
    # if n is odd then we will have 
    # only one middle element 
    if n % 2 != 0: 
        c = ( n // 2 ) + 1
        d = 0
          
    # if n is even then we will have two 
    # values 
    else: 
        c = ( n // 2 ) + 1
        d = ( n // 2 ) 
  
    for i in range( 1 , n + 1 ): 
        for j in range( 1 , n + 1 ): 
              
            # if i,j equals to corner row or 
            # column then "*" 
            if i == 1 or j == 1 or i == n or j == n: 
                print("*",end=" ") 
                  
            else: 
                  
                # if i,j equals to the middle row  
                # or column then  "*" 
                if i == c or j == c: 
                    print("*",end=" ") 
                      
                elif i == d or j == d: 
                    print("*",end=" ") 
                  
                else: 
                    print(" ",end=" ") 
          
        print() 
  
  
# Driver Code  
if __name__ == "__main__": 
    n = 7
    window_pattern(n) 

Output :

* * * * * * * 
*     *     * 
*     *     * 
* * * * * * * 
*     *     * 
*     *     * 
* * * * * * *

Time complexity: O(n^2)

My Personal Notes

Python3

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