Program to print the Zigzag pattern

Given a number N denoting the number of rows. The task is to print the zigzag pattern with N rows as shown in the below examples.

Examples:

Input : N = 3 
Output : 1 
         3*2 
         4*5*6

Input : N = 5
Output : 1 
         3*2 
         4*5*6 
         10*9*8*7 
         11*12*13*14*15

Approach:

  1. Use a for loop for printing the number of rows.
  2. Use two variables var and var1 for odd and even rows respectively.
  3. When the row number is odd, calculate starting point of the row and then print and increment the variable simultaneously.
  4. When the row number is even, calculate corresponding starting point and print and decrement the variable simultaneously.

Below is the implementation of the above approach:

C++

// CPP program to print the given
// zigzag pattern
  
#include<iostream>
using namespace std;
  
// Function to print the zigzag pattern 
void printPattern(int n)
{   
    int var1, var = 1;
      
    for(int i = 1; i <= n; i++)
    {   
        // for odd rows
        if(i%2!=0)
        {   
            // calculate starting value
            var = var + i - 1;
            for(int j=1; j<=i; j++)
            {
                if(j==1)
                {
                    cout<<var;
                }
                else
                   cout<<"*"<<var;
                     
               var++;    
            }
        }
        else // for even rows
        {         
            var1 = var + i -1; // calculate starting value 
            for(int j=1; j<=i; j++)
            {
                if(j==1)
                {
                    // print without star
                    cout<<var1;
                }
                else
                {
                    // print with star
                    cout<<"*"<<var1;
                }
                var1--;
            }
        
        cout<<endl;
    }
      
}
  
// Driver code
int main()
{
    int n = 5;
      
    printPattern(n);
      
    return 0;
}  

Java

// Java program to print the given 
// zigzag pattern 
class GFG
{
// Function to print the 
// zigzag pattern 
static void printPattern(int n) 
    int var1, var = 1
      
    for(int i = 1; i <= n; i++) 
    
        // for odd rows 
        if(i % 2 != 0
        
            // calculate starting value 
            var = var + i - 1
            for(int j = 1; j <= i; j++) 
            
                if(j == 1
                
                    System.out.print(var); 
                
                else
                System.out.print("*" + var); 
                      
            var++; 
            
        
        else // for even rows 
        {     
            var1 = var + i -1; // calculate starting value 
            for(int j = 1; j <= i; j++) 
            
                if(j == 1
                
                    // print without star 
                    System.out.print(var1); 
                
                else
                
                    // print with star 
                    System.out.print("*" + var1); 
                
                var1--; 
            
        
        System.out.print("\n"); 
    
      
  
// Driver code 
public static void main(String [] arg) 
    int n = 5
      
    printPattern(n); 
}
  
// This code is contributed by Smitha

C#

// C# program to print the given
// zigzag pattern
using System;
class GFG
{
// Function to print the
// zigzag pattern
static void printPattern(int n)
{
int var1, var = 1;

for(int i = 1; i <= n; i++) { // for odd rows if(i % 2 != 0) { // calculate starting value var = var + i - 1; for(int j = 1; j <= i; j++) { if(j == 1) { Console.Write(var); } else Console.Write("*" + var); var++; } } else // for even rows { var1 = var + i -1; // calculate starting value for(int j = 1; j <= i; j++) { if(j == 1) { // print without star Console.Write(var1); } else { // print with star Console.Write("*" + var1); } var1--; } } Console.Write("\n"); } } // Driver code public static void Main() { int n = 5; printPattern(n); } } // This code is contributed // by Akanksha Rai(Abby_akku) [tabbyending]

Output:

1
3*2
4*5*6
10*9*8*7
11*12*13*14*15


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