# Program to print the series 2, 15, 41, 80, 132, 197… till N terms

Given a number N, the task is to print the first N terms of the following series:

`2 15 41 80 132 197 275 366 470 587…`

Examples:

Input: N = 7

Output: 2 15 41 80 132 197 275

Input: N = 3

Output: 2 15 41

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: From the given series we can find the formula for Nth term:

1st term = 2
2nd term = 15 = 13 * 1 + 2
3rd term = 41 = 13 * 2 + 15 = 13 * 3 + 2
4th term = 80 = 13 * 3 + 41 = 13 * 6 + 2
5th term = 132 = 13 * 4 + 80 = 13 * 10 + 2
.
.
Nth term = (13 * N * (N – 1)) / 2 + 2

Therefore:

Nth term of the series Then iterate over numbers in the range [1, N] to find all the terms using the above formula and print them.

Below is the implementation of above approach:

## C++

 `// C++ implementation to print the  ` `// given with the given Nth term ` ` `  `#include "bits/stdc++.h" ` `using` `namespace` `std; ` ` `  `// Function to print the series ` `void` `printSeries(``int` `N) ` `{ ` ` `  `    ``int` `ith_term = 0; ` ` `  `    ``// Generate the ith term and ` `    ``for` `(``int` `i = 1; i <= N; i++) { ` ` `  `        ``ith_term = (13 * i * (i - 1)) / 2 + 2; ` `        ``cout << ith_term << ``", "``; ` `    ``} ` `} ` ` `  `// Driver Code ` `int` `main() ` `{ ` `    ``int` `N = 7; ` ` `  `    ``printSeries(N); ` `    ``return` `0; ` `} `

## Java

 `// Java implementation to print the  ` `// given with the given Nth term ` `import` `java.util.*; ` ` `  `class` `GFG{ ` ` `  `// Function to print the series ` `static` `void` `printSeries(``int` `N) ` `{ ` `    ``int` `ith_term = ``0``; ` `     `  `    ``// Generate the ith term and ` `    ``for``(``int` `i = ``1``; i <= N; i++) ` `    ``{ ` `       ``ith_term = (``13` `* i * (i - ``1``)) / ``2` `+ ``2``; ` `       ``System.out.print(ith_term + ``", "``); ` `    ``} ` `} ` ` `  `// Driver Code ` `public` `static` `void` `main(String[] args) ` `{ ` `    ``int` `N = ``7``; ` ` `  `    ``printSeries(N); ` `} ` `} ` ` `  `// This code is contributed by Rajput-Ji `

## Python3

 `# Python3 implementation to print the ` `# given with the given Nth term ` ` `  `# Function to print the series ` `def` `printSeries(N): ` `     `  `    ``ith_term ``=` `0``; ` ` `  `    ``# Generate the ith term and ` `    ``for` `i ``in` `range``(``1``, N ``+` `1``): ` `        ``ith_term ``=` `(``13` `*` `i ``*` `(i ``-` `1``)) ``/` `2` `+` `2``; ` `        ``print``(``int``(ith_term), ``", "``, end ``=` `""); ` ` `  `# Driver Code ` `if` `__name__ ``=``=` `'__main__'``: ` `     `  `    ``N ``=` `7``; ` `     `  `    ``printSeries(N); ` `     `  `# This code is contributed by amal kumar choubey `

## C#

 `// C# implementation to print the  ` `// given with the given Nth term ` `using` `System; ` ` `  `class` `GFG{ ` ` `  `// Function to print the series ` `static` `void` `printSeries(``int` `N) ` `{ ` `    ``int` `ith_term = 0; ` `     `  `    ``// Generate the ith term and ` `    ``for``(``int` `i = 1; i <= N; i++) ` `    ``{ ` `       ``ith_term = (13 * i * (i - 1)) / 2 + 2; ` `       ``Console.Write(ith_term + ``", "``); ` `    ``} ` `} ` ` `  `// Driver Code ` `public` `static` `void` `Main(String[] args) ` `{ ` `    ``int` `N = 7; ` ` `  `    ``printSeries(N); ` `} ` `} ` ` `  `// This code is contributed by Rajput-Ji `

Output:

```2, 15, 41, 80, 132, 197, 275,
```

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