Program to print the given digit in words
Given a number N, the task is to convert every digit of the number into words.
Examples:
Input: N = 1234
Output: One Two Three Four
Explanation:
Every digit of the given number has been converted into its corresponding word.Input: N = 567
Output: Five Six Seven
Approach: The idea is to traverse through every digit of the number and use switch-case. Since there are only ten possible values for digits, ten cases can be defined inside a switch block. For each digit, its corresponding case block will be executed and that digit will get printed in words.
Below is the implementation of the above approach:
CPP
// C++ implementation of the above approach #include "bits/stdc++.h" using namespace std; // Function to return the word // of the corresponding digit void printValue(char digit) { // Switch block to check for each digit c switch (digit) { // For digit 0 case '0': cout << "Zero "; break; // For digit 1 case '1': cout << "One "; break; // For digit 2 case '2': cout << "Two "; break; // For digit 3 case '3': cout << "Three "; break; // For digit 4 case '4': cout << "Four "; break; // For digit 5 case '5': cout << "Five "; break; // For digit 6 case '6': cout << "Six "; break; // For digit 7 case '7': cout << "Seven "; break; // For digit 8 case '8': cout << "Eight "; break; // For digit 9 case '9': cout << "Nine "; break; } } // Function to iterate through every // digit in the given number void printWord(string N) { int i, length = N.length(); // Finding each digit of the number for (i = 0; i < length; i++) { // Print the digit in words printValue(N[i]); } } // Driver code int main() { string N = "123"; printWord(N); return 0; } |
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Java
// Java implementation of the above approach class GFG { // Function to return the word // of the corresponding digit static void printValue(char digit) { // Switch block to check for each digit c switch (digit) { // For digit 0 case '0': System.out.print("Zero "); break; // For digit 1 case '1': System.out.print("One "); break; // For digit 2 case '2': System.out.print("Two "); break; // For digit 3 case '3': System.out.print("Three "); break; // For digit 4 case '4': System.out.print("Four "); break; // For digit 5 case '5': System.out.print("Five "); break; // For digit 6 case '6': System.out.print("Six "); break; // For digit 7 case '7': System.out.print("Seven "); break; // For digit 8 case '8': System.out.print("Eight "); break; // For digit 9 case '9': System.out.print("Nine "); break; } } // Function to iterate through every // digit in the given number static void printWord(String N) { int i, length = N.length(); // Finding each digit of the number for (i = 0; i < length; i++) { // Print the digit in words printValue(N.charAt(i)); } } // Driver code public static void main(String[] args) { String N = "123"; printWord(N); } } // This code is contributed by 29AjayKumar |
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Python3
# Python3 implementation of the above approach # Function to return the word # of the corresponding digit def printValue(digit): # Switch block to check for each digit c # For digit 0 if digit == '0': print("Zero ", end = " ") # For digit 1 elif digit == '1': print("One ", end = " ") # For digit 2 elif digit == '2': print("Two ", end = " ") #For digit 3 elif digit=='3': print("Three",end=" ") # For digit 4 elif digit == '4': print("Four ", end = " ") # For digit 5 elif digit == '5': print("Five ", end = " ") # For digit 6 elif digit == '6': print("Six ", end = " ") # For digit 7 elif digit == '7': print("Seven", end = " ") # For digit 8 elif digit == '8': print("Eight", end = " ") # For digit 9 elif digit == '9': print("Nine ", end = " ") # Function to iterate through every # digit in the given number def printWord(N): i = 0 length = len(N) # Finding each digit of the number while i < length: # Print the digit in words printValue(N[i]) i += 1 # Driver code N = "123"printWord(N) # This code is contributed by mohit kumar 29 |
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C#
// C# implementation of the above approach using System; class GFG { // Function to return the word // of the corresponding digit static void printValue(char digit) { // Switch block to check for each digit c switch (digit) { // For digit 0 case '0': Console.Write("Zero "); break; // For digit 1 case '1': Console.Write("One "); break; // For digit 2 case '2': Console.Write("Two "); break; // For digit 3 case '3': Console.Write("Three "); break; // For digit 4 case '4': Console.Write("Four "); break; // For digit 5 case '5': Console.Write("Five "); break; // For digit 6 case '6': Console.Write("Six "); break; // For digit 7 case '7': Console.Write("Seven "); break; // For digit 8 case '8': Console.Write("Eight "); break; // For digit 9 case '9': Console.Write("Nine "); break; } } // Function to iterate through every // digit in the given number static void printWord(string N) { int i, length = N.Length; // Finding each digit of the number for (i = 0; i < length; i++) { // Print the digit in words printValue(N[i]); } } // Driver code public static void Main() { string N = "123"; printWord(N); } } // This code is contributed by AnkitRai01 |
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Output:
One Two Three
Related Article: Print individual digits as words without using if or switch
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