Program to print the given digit in words

Given a number N, the task is to convert every digit of the number into words.

Examples:

Input: N = 1234
Output: One Two Three Four
Explanation:
Every digit of the given number has been converted into its corresponding word.

Input: N = 567
Output: Five Six Seven

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: The idea is to traverse through every digit of the number and use switch-case. Since there are only ten possible values for digits, ten cases can be defined inside a switch block. For each digit, its corresponding case block will be executed and that digit will get printed in words.

Below is the implementation of the above approach:

CPP

// C++ implementation of the above approach 
  
#include "bits/stdc++.h" 
using namespace std; 
  
// Function to return the word 
// of the corresponding digit 
void printValue(char digit) 
{ 
  
    // Switch block to check for each digit c 
    switch (digit) { 
  
    // For digit 0 
    case '0': 
        cout << "Zero "; 
        break; 
  
    // For digit 1 
    case '1': 
        cout << "One "; 
        break; 
  
    // For digit 2 
    case '2': 
        cout << "Two "; 
        break; 
  
    // For digit 3 
    case '3': 
        cout << "Three "; 
        break; 
  
    // For digit 4 
    case '4': 
        cout << "Four "; 
        break; 
  
    // For digit 5 
    case '5': 
        cout << "Five "; 
        break; 
  
    // For digit 6 
    case '6': 
        cout << "Six "; 
        break; 
  
    // For digit 7 
    case '7': 
        cout << "Seven "; 
        break; 
  
    // For digit 8 
    case '8': 
        cout << "Eight "; 
        break; 
  
    // For digit 9 
    case '9': 
        cout << "Nine "; 
        break; 
    } 
} 
  
// Function to iterate through every 
// digit in the given number 
void printWord(string N) 
{ 
    int i, length = N.length(); 
  
    // Finding each digit of the number 
    for (i = 0; i < length; i++) { 
  
        // Print the digit in words 
        printValue(N[i]); 
    } 
} 
  
// Driver code 
int main() 
{ 
    string N = "123"; 
    printWord(N); 
    return 0; 
} 

Java

// Java implementation of the above approach 
class GFG 
{ 
  
// Function to return the word 
// of the corresponding digit 
static void printValue(char digit) 
{ 
  
    // Switch block to check for each digit c 
    switch (digit) 
    { 
  
    // For digit 0 
    case '0': 
        System.out.print("Zero "); 
        break; 
  
    // For digit 1 
    case '1': 
        System.out.print("One "); 
        break; 
  
    // For digit 2 
    case '2': 
        System.out.print("Two "); 
        break; 
  
    // For digit 3 
    case '3': 
        System.out.print("Three "); 
        break; 
  
    // For digit 4 
    case '4': 
        System.out.print("Four "); 
        break; 
  
    // For digit 5 
    case '5': 
        System.out.print("Five "); 
        break; 
  
    // For digit 6 
    case '6': 
        System.out.print("Six "); 
        break; 
  
    // For digit 7 
    case '7': 
        System.out.print("Seven "); 
        break; 
  
    // For digit 8 
    case '8': 
        System.out.print("Eight "); 
        break; 
  
    // For digit 9 
    case '9': 
        System.out.print("Nine "); 
        break; 
    } 
} 
  
// Function to iterate through every 
// digit in the given number 
static void printWord(String N) 
{ 
    int i, length = N.length(); 
  
    // Finding each digit of the number 
    for (i = 0; i < length; i++) 
    { 
  
        // Print the digit in words 
        printValue(N.charAt(i)); 
    } 
} 
  
// Driver code 
public static void main(String[] args) 
{ 
    String N = "123"; 
    printWord(N); 
} 
} 
  
// This code is contributed by 29AjayKumar 

Python3

# Python3 implementation of the above approach 
  
# Function to return the word 
# of the corresponding digit 
def printValue(digit): 
  
    # Switch block to check for each digit c 
  
    # For digit 0 
    if digit == '0': 
        print("Zero ", end = " ") 
  
    # For digit 1 
    elif digit == '1': 
        print("One ", end = " ") 
  
    # For digit 2 
    elif digit == '2': 
        print("Two ", end = " ") 
  
    #For digit 3 
    elif digit=='3': 
        print("Three",end=" ") 
  
    # For digit 4 
    elif digit == '4': 
        print("Four ", end = " ") 
  
    # For digit 5 
    elif digit == '5': 
        print("Five ", end = " ") 
  
    # For digit 6 
    elif digit == '6': 
        print("Six ", end = " ") 
  
    # For digit 7 
    elif digit == '7': 
        print("Seven", end = " ") 
  
    # For digit 8 
    elif digit == '8': 
        print("Eight", end = " ") 
  
    # For digit 9 
    elif digit == '9': 
        print("Nine ", end = " ") 
  
# Function to iterate through every 
# digit in the given number 
def printWord(N): 
    i = 0
    length = len(N) 
  
    # Finding each digit of the number 
    while i < length: 
          
        # Print the digit in words 
        printValue(N[i]) 
        i += 1
  
# Driver code 
N = "123"
printWord(N) 
  
# This code is contributed by mohit kumar 29 

C#

// C# implementation of the above approach 
using System; 
  
class GFG 
{ 
  
    // Function to return the word 
    // of the corresponding digit 
    static void printValue(char digit) 
    { 
      
        // Switch block to check for each digit c 
        switch (digit) 
        { 
      
        // For digit 0 
        case '0': 
            Console.Write("Zero "); 
            break; 
      
        // For digit 1 
        case '1': 
            Console.Write("One "); 
            break; 
      
        // For digit 2 
        case '2': 
            Console.Write("Two "); 
            break; 
      
        // For digit 3 
        case '3': 
            Console.Write("Three "); 
            break; 
      
        // For digit 4 
        case '4': 
            Console.Write("Four "); 
            break; 
      
        // For digit 5 
        case '5': 
            Console.Write("Five "); 
            break; 
      
        // For digit 6 
        case '6': 
            Console.Write("Six "); 
            break; 
      
        // For digit 7 
        case '7': 
            Console.Write("Seven "); 
            break; 
      
        // For digit 8 
        case '8': 
            Console.Write("Eight "); 
            break; 
      
        // For digit 9 
        case '9': 
            Console.Write("Nine "); 
            break; 
        } 
    } 
      
    // Function to iterate through every 
    // digit in the given number 
    static void printWord(string N) 
    { 
        int i, length = N.Length; 
      
        // Finding each digit of the number 
        for (i = 0; i < length; i++) 
        { 
      
            // Print the digit in words 
            printValue(N[i]); 
        } 
    } 
      
    // Driver code 
    public static void Main() 
    { 
        string N = "123"; 
        printWord(N); 
    } 
} 
  
// This code is contributed by AnkitRai01 

Output:

One Two Three

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My Personal Notes

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

CPP

Java

Python3

C#

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