Program to print N minimum elements from list of integers

Given a list of integers, the task is to generate another list with N minimum elements.

Examples:

Input: {23, 1, 6, 2, 90}
Output: {1, 2}

Input: {34, 21, 56, 42, 89, 90, -1}
Output: {-1, 21}

Approach: The idea is to use the concept used in Find the smallest and second smallest elements in an array.

  • First, find the smallest number in the given list.
  • Then add that current minimum element to another list that will contain the N minimum elements.
  • Remove the current minimum element from the given list.
  • Continue with the same process until the N minimum elements are found.

Below is the implementation of the above approach:

C++

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// C++ program to find N 
// minimum elements
#include <bits/stdc++.h>
using namespace std;
  
void Nminelements(vector<int>list1, int N)
{
    vector<int> final_list;
    int n = list1.size();
    for (int i = 0; i < N; i++) 
    {
        int min1 = 9999999;
        for (int j = 0; j < n; j++)
        {
            if (list1[j] < min1)
                min1 = list1[j];
        }
          
        // remove minimum element 
        // from list so that it do
        // not come in calculation again         
        list1.erase(remove(list1.begin(), 
                           list1.end(), min1), 
                           list1.end());
        final_list.push_back(min1);
    }
    for(int i = 0; i < final_list.size(); i++)
    cout << final_list[i] << " ";
} 
  
// Driver code
int main()
{
    vector<int> list1 = {4, 78, 34, 10, 
                         8, 21, 11, 231};
    int N = 2;
    Nminelements(list1, N);
}
  
// This code is contributed by Subhadeep

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# Python program to find N minimum elements 


def Nminelements(list1, N): 


    final_list =[]; 


   


    for i in range(0, N):     


        min1 = 9999999; 


           


        for j in range(len(list1)):       


            if list1[j]<min1: 


                min1 = list1[j]; 


  


        # remove minimum element from list so  


        # that it do not come in calculation again          


        list1.remove(min1); 


        final_list.append(min1) 


           


    print(final_list) 


   


# Driver code 


list1 = [4, 78, 34, 10, 8, 21, 11, 231]; 


N = 2; 


Nminelements(list1, N) 



















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Output:


4 8






          
          
          
          

            

    

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