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Program to print N minimum elements from list of integers
• Difficulty Level : Basic
• Last Updated : 25 Jan, 2021

Given a list of integers, the task is to generate another list with N minimum elements.

Examples:

```Input: {23, 1, 6, 2, 90}
Output: {1, 2}

Input: {34, 21, 56, 42, 89, 90, -1}
Output: {-1, 21}```

Approach: The idea is to use the concept used in Find the smallest and second smallest elements in an array

• First, find the smallest number in the given list.
• Then add that current minimum element to another list that will contain the N minimum elements.
• Remove the current minimum element from the given list.
• Continue with the same process until the N minimum elements are found.

Below is the implementation of the above approach:

## C++

 `// C++ program to find N ` `// minimum elements` `#include ` `using` `namespace` `std;`   `void` `Nminelements(vector<``int``>list1, ``int` `N)` `{` `    ``vector<``int``> final_list;` `    ``int` `n = list1.size();` `    ``for` `(``int` `i = 0; i < N; i++) ` `    ``{` `        ``int` `min1 = 9999999;` `        ``for` `(``int` `j = 0; j < n; j++)` `        ``{` `            ``if` `(list1[j] < min1)` `                ``min1 = list1[j];` `        ``}` `        `  `        ``// remove minimum element ` `        ``// from list so that it do` `        ``// not come in calculation again         ` `        ``list1.erase(``remove``(list1.begin(), ` `                           ``list1.end(), min1), ` `                           ``list1.end());` `        ``final_list.push_back(min1);` `    ``}` `    ``for``(``int` `i = 0; i < final_list.size(); i++)` `    ``cout << final_list[i] << ``" "``;` `} `   `// Driver code` `int` `main()` `{` `    ``vector<``int``> list1 = {4, 78, 34, 10, ` `                         ``8, 21, 11, 231};` `    ``int` `N = 2;` `    ``Nminelements(list1, N);` `}`   `// This code is contributed by Subhadeep`

## Python3

 `# Python3 program to find N minimum elements` `def` `Nminelements(list1, N):` `    ``final_list ``=``[];` ` `  `    ``for` `i ``in` `range``(``0``, N):    ` `        ``min1 ``=` `9999999``;` `         `  `        ``for` `j ``in` `range``(``len``(list1)):      ` `            ``if` `list1[j]

## C#

 `// C# program to find N` `// minimum elements` `using` `System;` `using` `System.Collections;`   `class` `GFG{`   `static` `void` `Nminelements(ArrayList list1, ``int` `N)` `{` `    ``ArrayList final_list = ``new` `ArrayList();`   `    ``for``(``int` `i = 0; i < N; i++) ` `    ``{` `        ``int` `min1 = 9999999;` `        ``for``(``int` `j = 0; j < list1.Count; j++)` `        ``{` `            ``if` `((``int``)list1[j] < min1)` `                ``min1 = (``int``)list1[j];` `        ``}` `        `  `        ``// Remove minimum element` `        ``// from list so that it do` `        ``// not come in calculation again` `        ``list1.Remove(min1);`   `        ``final_list.Add(min1);` `    ``}` `    ``for``(``int` `i = 0; i < final_list.Count; i++)` `        ``Console.Write(final_list[i] + ``" "``);` `}`   `// Driver code` `public` `static` `void` `Main()` `{` `    ``ArrayList list1 = ``new` `ArrayList(){ 4, 78, 34, 10, ` `                                       ``8, 21, 11, 231 };` `    ``int` `N = 2;` `    `  `    ``Nminelements(list1, N);` `}` `}`   `// This code is contributed by chitranayal`

Output:

`4 8`

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