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Program to print first 10 perfect squares

Last Updated : 09 Jan, 2024
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Write a program to print the first 10 perfect squares. A perfect square is an integer which is the square of some other integer, or we can say that it is a second exponent of an integer

Output format:

1 4 9 16 25 ….

Approach:

We know that the first 10 perfect squares will be square of 1, square of 2, square of 3... till square of 10. So, iterate from 1 to 10 and print squares of each number.

Step-by-step algorithm:

  • Run a loop for i = 1 to 10:
    • For each iteration, calculate sq = i * i
    • Print the square as sq.
  • After 10 iterations, we will have the first 10 perfect squares.

Below is the implementation of the above approach:

C++




#include <iostream>
using namespace std;
 
int main() {
     
    for(int i = 1; i <= 10; i++) {
        int sq = i * i;
        cout << sq << " ";
    }
    return 0;
}


Java




/*package whatever //do not write package name here */
public class Main {
    public static void main(String[] args) {
        for (int i = 1; i <= 10; i++) {
            int sq = i * i;
            System.out.print(sq + " ");
        }
    }
}


Python3




# code by flutterfly
for i in range(1, 11):
    sq = i * i
    print(sq, end=" ")


C#




//code by flutterfly
using System;
 
class Program {
    static void Main() {
        for (int i = 1; i <= 10; i++) {
            int sq = i * i;
            Console.Write(sq + " ");
        }
    }
}


Javascript




//code by flutterfly
for (let i = 1; i <= 10; i++) {
    let sq = i * i;
    process.stdout.write(sq + " ");
}


Output

1 4 9 16 25 36 49 64 81 100 

Time Complexity: O(1)
Auxiliary Space: O(1)



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