# Program to print all the numbers divisible by 5 or 7 for a given number

Given the integer N, the task is to print all the numbers less than N, which are divisible by 5 or 7.

Examples :

```Input : 20
Output : 5 7 10 14 15 20

Input: 50
Output: 5 7 10 14 15 20 21 25 28 30 35 40 42 45 49 50
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: For example, let’s take N = 20 as a limit, then the program should print all numbers less than 20 which are divisible by both 5 or 7. For this divide each number from 0 to N by both 5 and 7 and check their remainder. If the remainder is 0 in both cases then simply print that number.

Below is the implementaion :

## C++

 `// C++ program to print all the numbers  ` `// divisible by 5 or 7 for a given number  ` `# include ` `using` `namespace` `std; ` ` `  `// Result generator with N  ` `int` `NumGen(``int` `n) ` `{ ` ` `  `    ``// Iterate from 0 to N ` `    ``for``(``int` `j = 1; j < n + 1; j++) ` `    ``{ ` ` `  `        ``// Short-circuit operator is used  ` `        ``if` `(j % 5 == 0 || j % 7 == 0) ` `            ``cout << j << ``" "``; ` `    ``} ` `    ``return` `n; ` `} ` ` `  `// Driver code  ` `int` `main() ` `{  ` `    ``// Input goes here  ` `    ``int` `N = 50; ` `     `  `    ``// Iterating over generator function ` `    ``NumGen(N); ` `     `  `    ``return` `0; ` `} ` ` `  `// This code is contributed by Code_Mech `

## Java

 `// Java program to print all the numbers  ` `// divisible by 5 or 7 for a given number  ` `import` `java.util.*; ` ` `  `class` `GFG{ ` `     `  `// Result generator with N  ` `static` `int` `NumGen(``int` `n) ` `{ ` ` `  `    ``// Iterate from 0 to N ` `    ``for``(``int` `j = ``1``; j < n + ``1``; j++) ` `    ``{ ` ` `  `       ``// Short-circuit operator is used  ` `       ``if` `(j % ``5` `== ``0` `|| j % ``7` `== ``0``) ` `           ``System.out.print(j + ``" "``); ` `    ``} ` `    ``return` `n; ` `} ` ` `  `// Driver code  ` `public` `static` `void` `main(String args[]) ` `{  ` `    ``// Input goes here  ` `    ``int` `N = ``50``; ` `     `  `    ``// Iterating over generator function ` `    ``NumGen(N); ` `} ` `} ` ` `  `// This code is contributed by AbhiThakur `

## Python3

 `# Python3 program to print all the numbers  ` `# divisible by 5 or 7 for a given number  ` ` `  `# Result generator with N  ` `def` `NumGen(n): ` `     `  `    ``# iterate from 0 to N ` `    ``for` `j ``in` `range``(``1``, n``+``1``): ` ` `  `        ``# Short-circuit operator is used  ` `        ``if` `j ``%` `5` `=``=` `0` `or` `j ``%` `7` `=``=` `0``: ` `            ``yield` `j ` ` `  `# Driver code  ` `if` `__name__ ``=``=` `"__main__"``:  ` `       `  `    ``# input goes here  ` `    ``N ``=` `50` ` `  `    ``# Iterating over generator function ` `    ``for` `j ``in` `NumGen(N): ` `        ``print``(j, end ``=` `" "``) `

## C#

 `// C# program to print all the numbers  ` `// divisible by 5 or 7 for a given number  ` `using` `System; ` ` `  `class` `GFG{ ` `     `  `// Result generator with N  ` `static` `int` `NumGen(``int` `n) ` `{ ` ` `  `    ``// Iterate from 0 to N ` `    ``for``(``int` `j = 1; j < n + 1; j++) ` `    ``{ ` ` `  `       ``// Short-circuit operator is used  ` `       ``if` `(j % 5 == 0 || j % 7 == 0) ` `           ``Console.Write(j + ``" "``); ` `    ``} ` `    ``return` `n; ` `} ` ` `  `// Driver code  ` `public` `static` `void` `Main() ` `{  ` ` `  `    ``// Input goes here  ` `    ``int` `N = 50; ` `     `  `    ``// Iterating over generator ` `    ``// function ` `    ``NumGen(N); ` `} ` `} ` ` `  `// This code is contributed by Code_Mech `

Output:

```5 7 10 14 15 20 21 25 28 30 35 40 42 45 49 50
```

Attention geek! Strengthen your foundations with the Python Programming Foundation Course and learn the basics.

To begin with, your interview preparations Enhance your Data Structures concepts with the Python DS Course.

My Personal Notes arrow_drop_up Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.

Article Tags :

Be the First to upvote.

Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.