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Program to print all the numbers divisible by 5 or 7 for a given number
• Last Updated : 02 Jun, 2020

Given the integer N, the task is to print all the numbers less than N, which are divisible by 5 or 7.

Examples :

```Input : 20
Output : 5 7 10 14 15 20

Input: 50
Output: 5 7 10 14 15 20 21 25 28 30 35 40 42 45 49 50
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: For example, let’s take N = 20 as a limit, then the program should print all numbers less than 20 which are divisible by both 5 or 7. For this divide each number from 0 to N by both 5 and 7 and check their remainder. If the remainder is 0 in both cases then simply print that number.

Below is the implementaion :

## C++

 `// C++ program to print all the numbers  ` `// divisible by 5 or 7 for a given number  ` `# include ` `using` `namespace` `std; ` ` `  `// Result generator with N  ` `int` `NumGen(``int` `n) ` `{ ` ` `  `    ``// Iterate from 0 to N ` `    ``for``(``int` `j = 1; j < n + 1; j++) ` `    ``{ ` ` `  `        ``// Short-circuit operator is used  ` `        ``if` `(j % 5 == 0 || j % 7 == 0) ` `            ``cout << j << ``" "``; ` `    ``} ` `    ``return` `n; ` `} ` ` `  `// Driver code  ` `int` `main() ` `{  ` `    ``// Input goes here  ` `    ``int` `N = 50; ` `     `  `    ``// Iterating over generator function ` `    ``NumGen(N); ` `     `  `    ``return` `0; ` `} ` ` `  `// This code is contributed by Code_Mech `

## Java

 `// Java program to print all the numbers  ` `// divisible by 5 or 7 for a given number  ` `import` `java.util.*; ` ` `  `class` `GFG{ ` `     `  `// Result generator with N  ` `static` `int` `NumGen(``int` `n) ` `{ ` ` `  `    ``// Iterate from 0 to N ` `    ``for``(``int` `j = ``1``; j < n + ``1``; j++) ` `    ``{ ` ` `  `       ``// Short-circuit operator is used  ` `       ``if` `(j % ``5` `== ``0` `|| j % ``7` `== ``0``) ` `           ``System.out.print(j + ``" "``); ` `    ``} ` `    ``return` `n; ` `} ` ` `  `// Driver code  ` `public` `static` `void` `main(String args[]) ` `{  ` `    ``// Input goes here  ` `    ``int` `N = ``50``; ` `     `  `    ``// Iterating over generator function ` `    ``NumGen(N); ` `} ` `} ` ` `  `// This code is contributed by AbhiThakur `

## Python3

 `# Python3 program to print all the numbers  ` `# divisible by 5 or 7 for a given number  ` ` `  `# Result generator with N  ` `def` `NumGen(n): ` `     `  `    ``# iterate from 0 to N ` `    ``for` `j ``in` `range``(``1``, n``+``1``): ` ` `  `        ``# Short-circuit operator is used  ` `        ``if` `j ``%` `5` `=``=` `0` `or` `j ``%` `7` `=``=` `0``: ` `            ``yield` `j ` ` `  `# Driver code  ` `if` `__name__ ``=``=` `"__main__"``:  ` `       `  `    ``# input goes here  ` `    ``N ``=` `50` ` `  `    ``# Iterating over generator function ` `    ``for` `j ``in` `NumGen(N): ` `        ``print``(j, end ``=` `" "``) `

## C#

 `// C# program to print all the numbers  ` `// divisible by 5 or 7 for a given number  ` `using` `System; ` ` `  `class` `GFG{ ` `     `  `// Result generator with N  ` `static` `int` `NumGen(``int` `n) ` `{ ` ` `  `    ``// Iterate from 0 to N ` `    ``for``(``int` `j = 1; j < n + 1; j++) ` `    ``{ ` ` `  `       ``// Short-circuit operator is used  ` `       ``if` `(j % 5 == 0 || j % 7 == 0) ` `           ``Console.Write(j + ``" "``); ` `    ``} ` `    ``return` `n; ` `} ` ` `  `// Driver code  ` `public` `static` `void` `Main() ` `{  ` ` `  `    ``// Input goes here  ` `    ``int` `N = 50; ` `     `  `    ``// Iterating over generator ` `    ``// function ` `    ``NumGen(N); ` `} ` `} ` ` `  `// This code is contributed by Code_Mech `

Output:

```5 7 10 14 15 20 21 25 28 30 35 40 42 45 49 50
```

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