A certain number of men can do a certain piece of work in D days. If there were m more men engaged in the work then the work can be done in d days less. The task is to find how many men were there initially.
Examples:
Input: D = 5, m = 4, d = 4
Output: 1Input: D = 180, m = 30, d = 20
Output: 240
Approach: Let the initial number of men be M and days be D
Amount of work completed M men in D days will be M * D
i.e. Work Done = M * D …(1)
If there are M + m men then the same amount of work is completed in D – d days.
i.e. Work Done = (M + m) * (D – d) …(2)
Equating equations 1 and 2,
M * D = (M + m) * (D – d)
M * D = M * (D – d) + m * (D – d)
M * D – M * (D – d) = m * (D – d)
M * (D – (D – d)) = m * (D – d)
M = m * (D – d) / d
Below is the implementation of the above approach:
C++
// C++ implementation of above approach. #include <bits/stdc++.h> using namespace std; // Function to return the // number of men initially int numberOfMen(int D, int m, int d) { int Men = (m * (D - d)) / d; return Men; } // Driver code int main() { int D = 5, m = 4, d = 4; cout << numberOfMen(D, m, d); return 0; } |
Java
// Java implementation of the approach import java.util.*; class GFG { // Function to return the // number of men initially static int numberOfMen(int D, int m, int d) { int Men = (m * (D - d)) / d; return Men; } // Driver code public static void main(String args[]) { int D = 5, m = 4, d = 4; System.out.println(numberOfMen(D, m, d)); } } // This code is contributed by Arnab Kundu |
Python3
# Python implementation of above approach. # Function to return the # number of men initially def numberOfMen(D, m, d): Men = (m * (D - d)) / d; return int(Men); # Driver code D = 5; m = 4; d = 4; print(numberOfMen(D, m, d)); # This code contributed by Rajput-Ji |
C#
// C# implementation of the approach using System; class GFG { // Function to return the // number of men initially static int numberOfMen(int D, int m, int d) { int Men = (m * (D - d)) / d; return Men; } // Driver code public static void Main() { int D = 5, m = 4, d = 4; Console.WriteLine(numberOfMen(D, m, d)); } } // This code is contributed by anuj_67.. |
1
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