Given a number N. The task is to write a program to find the Nth term of the below series:
0, 5, 18, 39, 67, 105, 150, 203, …(N Terms)
Examples:
Input: N = 4 Output: 82 For N = 4 4th Term = ( 4 * 4 * 4 - 7 * 4 + 3) = 39 Input: N = 10 Output: 332
Approach: The generalized Nth term of this series:
Below is the required implementation:
C++
// CPP program to find the N-th term of the series: // 0, 5, 18, 39, 67, 105, 150, 203, ... #include <iostream> #include <math.h> using namespace std;
// calculate Nth term of series int nthTerm( int n)
{ return 4 * pow (n, 2) - 7 * n + 3;
} // Driver code int main()
{ int N = 4;
cout << nthTerm(N);
return 0;
} |
Java
// Java program to find the N-th term of the series: // 0, 5, 18, 39, 67, 105, 150, 203, import java.util.*;
import java.lang.*;
import java.io.*;
class GFG
{ // calculate Nth term of series static int nthTerm( int n)
{ return 4 * ( int )Math.pow(n, 2 ) - 7 * n + 3 ;
} // Driver code public static void main(String args[])
{ int N = 4 ;
System.out.print(nthTerm(N));
} } |
Python 3
# Python 3 program to find the # N-th term of the series: # 0, 5, 18, 39, 67, 105, 150, 203, ... # calculate Nth term of series def nthTerm(n):
return 4 * pow (n, 2 ) - 7 * n + 3
# Driver code N = 4
print (nthTerm(N))
# This code is contributed by ash264 |
C#
// C# program to find the // N-th term of the series: // 0, 5, 18, 39, 67, 105, 150, 203, using System;
class GFG
{ // calculate Nth term of series static int nthTerm( int n)
{ return 4 * ( int )Math.Pow(n, 2) -
7 * n + 3;
} // Driver code static public void Main ()
{ int N = 4;
Console.Write(nthTerm(N));
} } // This code is contributed by Raj |
PHP
<?php // PHP program to find the // N-th term of the series: // 0, 5, 18, 39, 67, 105, 150, 203, ... // calculate Nth term of series function nthTerm( $n )
{ return 4 * pow( $n , 2) -
7 * $n + 3;
} // Driver code $N = 4;
echo nthTerm( $N );
// This code is contributed // by Akanksha Rai(Abby_akku) ?> |
Javascript
<script> // JavaScript program to find the N-th term of the series: // 0, 5, 18, 39, 67, 105, 150, 203, ... // calculate Nth term of series function nthTerm( n)
{ return 4 * Math.pow(n, 2) - 7 * n + 3;
} // driver code // declaration of number of terms
let N = 4;
document.write( nthTerm(N) );
// This code contributed by gauravrajput1 </script> |
Output:
39
Time Complexity: O(1)
Space Complexity: O(1) since using constant variables