Program to find the Nth term of the series 0, 5, 18, 39, 67, 105, 150, 203, …
Given a number N. The task is to write a program to find the Nth term of the below series:
0, 5, 18, 39, 67, 105, 150, 203, …(N Terms)
Examples:
Input: N = 4
Output: 82
For N = 4
4th Term = ( 4 * 4 * 4 - 7 * 4 + 3)
= 39
Input: N = 10
Output: 332
Approach: The generalized Nth term of this series:
Below is the required implementation:
C++
#include <iostream>
#include <math.h>
using namespace std;
int nthTerm( int n)
{
return 4 * pow (n, 2) - 7 * n + 3;
}
int main()
{
int N = 4;
cout << nthTerm(N);
return 0;
}
|
Java
import java.util.*;
import java.lang.*;
import java.io.*;
class GFG
{
static int nthTerm( int n)
{
return 4 * ( int )Math.pow(n, 2 ) - 7 * n + 3 ;
}
public static void main(String args[])
{
int N = 4 ;
System.out.print(nthTerm(N));
}
}
|
Python 3
def nthTerm(n):
return 4 * pow (n, 2 ) - 7 * n + 3
N = 4
print (nthTerm(N))
|
C#
using System;
class GFG
{
static int nthTerm( int n)
{
return 4 * ( int )Math.Pow(n, 2) -
7 * n + 3;
}
static public void Main ()
{
int N = 4;
Console.Write(nthTerm(N));
}
}
|
PHP
<?php
function nthTerm( $n )
{
return 4 * pow( $n , 2) -
7 * $n + 3;
}
$N = 4;
echo nthTerm( $N );
?>
|
Javascript
<script>
function nthTerm( n)
{
return 4 * Math.pow(n, 2) - 7 * n + 3;
}
let N = 4;
document.write( nthTerm(N) );
</script>
|
Time Complexity: O(1)
Space Complexity: O(1) since using constant variables
Last Updated :
28 Jul, 2022
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