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Program to find the Nth term of series 5, 12, 21, 32, 45……

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  • Last Updated : 27 Aug, 2022
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Given a number N, The task is to write a program to find the Nth term of the below series: 
 

5, 12, 21, 32, 45…… 
 

Examples: 
 

Input: N = 2
Output: 12

Input: N = 5
Output: 45

 

Approach: 
The generalized Nth term of this series: 
 

Nth Term : n*n + 4*n 
 

Below is the required implementation: 
 

C++




// CPP program to find
// the N-th term of the series:
// 5, 12, 21, 32, 45......
 
#include <iostream>
#include <math.h>
using namespace std;
 
// calculate Nth term of series
int nthTerm(int n)
{
    return pow(n, 2) + 4 * n;
}
 
// Driver code
int main()
{
 
    // Get N
    int N = 4;
 
    // Get the Nth term
    cout << nthTerm(N) << endl;
 
    return 0;
}

C




// C program to find
// the N-th term of the series:
// 5, 12, 21, 32, 45......
#include <stdio.h>
#include <math.h>
 
// calculate Nth term of series
int nthTerm(int n)
{
    return pow(n, 2) + 4 * n;
}
 
// Driver code
int main()
{
 
    // Get N
    int N = 4;
 
    // Get the Nth term
    printf("%d\n",nthTerm(N));
 
    return 0;
}
 
// This code is contributed by kothavvsaakash.

Java




// Java  program to find
// the N-th term of the series:
// 5, 12, 21, 32, 45......
import java.io.*;
 
class GFG {
     
 
 
// calculate Nth term of series
static int nthTerm(int n)
{
    return (int)Math.pow(n, 2) + 4 * n;
}
 
// Driver code
 
    public static void main (String[] args) {
     
    // Get N
    int N = 4;
 
    // Get the Nth term
    System.out.println( nthTerm(N));
 
    }
}
// This code is contributed
// by  inder_verma

Python3




# Python3 program to find
# the N-th term of the series:
# 5, 12, 21, 32, 45......
 
# calculate Nth term of series
def nthTerm(n):
    return n ** 2 + 4 * n;
 
# Driver code
 
# Get N
N = 4
 
# Get the Nth term
print(nthTerm(N))
 
# This code is contributed by Raj

C#




// C# program to find the
// N-th term of the series:
// 5, 12, 21, 32, 45......
using System;
 
class GFG
{
     
// calculate Nth term of series
static int nthTerm(int n)
{
    return (int)Math.Pow(n, 2) + 4 * n;
}
 
// Driver code
public static void Main ()
{
 
    // Get N
    int N = 4;
     
    // Get the Nth term
    Console.WriteLine(nthTerm(N));
}
}
 
// This code is contributed
// by sh..

PHP




<?php
// PHP program to find
// the N-th term of the series:
// 5, 12, 21, 32, 45......
 
// calculate Nth term of series
function nthTerm($n)
{
    return pow($n, 2) + 4 * $n;
}
 
// Driver code
$N = 4;
 
// Get the Nth term
echo nthTerm($N);
 
// This code is contributed
// by Mahadev99
?>

Javascript




<script>
// JavaScript program to find
// the N-th term of the series:
// 5, 12, 21, 32, 45......
 
 
// calculate Nth term of series
function nthTerm( n)
{
    return Math.pow(n, 2) + 4 * n;
}
 
// Driver code
    // Get N
    let N = 4;
 
    // Get the Nth term
    document.write( nthTerm(N));
 
// This code is contributed by todaysgaurav
 
</script>

Output: 

32

 

Time complexity: O(1), since there is no loop or recursion.

Auxiliary Space: O(1), since no extra space has been taken.


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