Given two positive integers **A** and **B**, representing the length of the semi-major and semi-minor axis of an ellipse of the equation , the task is to find the eccentricity of the given ellipse.

**Examples:**

Input:A = 12, B = 9Output:0.66

Input:A = 6, B = 3Output:0.87

**Approach:** The given problem can be solved based on the following formula to calculate the eccentricity of an ellipse which is given by:

where,

A = Length of semi major axis

B = Length of semi minor axis

Therefore, print the value of as the eccentricity of the ellipse.

Below is the implementation of the above approach:

## C++

`// C++ program for the above approach` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// Function to find the` `// eccentricity of ellipse` `void` `findEccentricity(` `double` `A,` ` ` `double` `B)` `{` ` ` `// Store the squares of length of` ` ` `// semi-major and semi-minor axis` ` ` `double` `semiMajor = A * A;` ` ` `double` `semiMinor = B * B;` ` ` `// Calculate the eccentricity` ` ` `double` `ans = ` `sqrt` `(1 - semiMinor / semiMajor);` ` ` `// Print the result` ` ` `cout << fixed << setprecision(2)` ` ` `<< ans;` `}` `// Driver Code` `int` `main()` `{` ` ` `double` `A = 12, B = 9;` ` ` `findEccentricity(A, B);` ` ` `return` `0;` `}` |

## Java

`// Java program for the above approach` `import` `java.util.*;` `class` `GFG{` `// Function to find the` `// eccentricity of ellipse` `static` `void` `findEccentricity(` `double` `A, ` `double` `B)` `{` ` ` `// Store the squares of length of` ` ` `// semi-major and semi-minor axis` ` ` `double` `semiMajor = A * A;` ` ` `double` `semiMinor = B * B;` ` ` ` ` `// Calculate the eccentricity` ` ` `double` `ans = Math.sqrt(` `1` `- semiMinor / semiMajor);` ` ` `// Print the result` ` ` `System.out.format(` `"%.2f"` `, ans);` `}` `// Driver Code` `public` `static` `void` `main(String arr[])` `{` ` ` `double` `A = ` `12` `, B = ` `9` `;` ` ` `findEccentricity(A, B);` `}` `}` `// This code is contributed by kirti` |

## Python3

`# Python3 program for the above approach` `import` `math` `# Function to find the` `# eccentricity of ellipse` `def` `findEccentricity(A, B):` ` ` ` ` `# Store the squares of length of` ` ` `# semi-major and semi-minor axis` ` ` `semiMajor ` `=` `A ` `*` `A` ` ` `semiMinor ` `=` `B ` `*` `B` ` ` `# Calculate the eccentricity` ` ` `ans ` `=` `math.sqrt(` `1` `-` `semiMinor ` `/` `semiMajor)` ` ` `# Print the result` ` ` `print` `(` `'%.2f'` `%` `ans)` `# Driver Code` `if` `__name__ ` `=` `=` `"__main__"` `:` ` ` `A ` `=` `12` ` ` `B ` `=` `9` ` ` ` ` `findEccentricity(A, B)` ` ` `# This code is contributed by ukasp` |

## C#

`// C# program for the above approach` `using` `System;` `class` `GFG{` `// Function to find the` `// eccentricity of ellipse` `static` `void` `findEccentricity(` `double` `A, ` `double` `B)` `{` ` ` ` ` `// Store the squares of length of` ` ` `// semi-major and semi-minor axis` ` ` `double` `semiMajor = A * A;` ` ` `double` `semiMinor = B * B;` ` ` ` ` `// Calculate the eccentricity` ` ` `double` `ans = Math.Sqrt(1 - semiMinor / semiMajor);` ` ` ` ` `// Print the result` ` ` `Console.Write(Math.Round(ans, 2));` `}` `// Driver code` `static` `void` `Main()` `{` ` ` `double` `A = 12, B = 9;` ` ` ` ` `findEccentricity(A, B);` `}` `}` `// This code is contributed by code_hunt` |

## Javascript

`<script>` `// Javascript program for the above approach` `// Function to find the` `// eccentricity of ellipse` `function` `findEccentricity(A, B)` `{` ` ` `var` `semiMajor = A * A;` ` ` `var` `semiMinor = B * B;` ` ` `var` `ans = Math.sqrt(1 - semiMinor / semiMajor)` ` ` ` ` `return` `ans.toFixed(2);` `}` ` ` `// Driver Code` `var` `A = 12;` `var` `B = 9;` `document.write(findEccentricity(A, B));` ` ` `// This code is contributed by bunnyram19` ` ` `</script>` |

**Output:**

0.66

**Time Complexity:** O(1)**Auxiliary Space:** O(1)

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