Skip to content
Related Articles

Related Articles

Program to find the angles of a quadrilateral

View Discussion
Improve Article
Save Article
Like Article
  • Last Updated : 16 Jun, 2022

Given that all the angles of a quadrilateral are in AP having common difference ‘d’, the task is to find all the angles.
Examples: 
 

Input: d = 10
Output: 75, 85, 95, 105

Input: d = 20
Output: 60, 80, 100, 120

 

Approach:
 

We know that the angles of the quadrilateral are in AP and having the common difference ‘d’. 
So, if we assume the first angle to be ‘a’ then the other angles can be calculated as, 
‘a+d’, ‘a+2d’ and ‘a+3d’ 
And, from the properties of quadrilaterals, the sum of all the angles of a quadrilateral is 360. So, 
(a) + (a + d) + (a + 2*d) + (a + 3*d) = 360 
4*a + 6*d = 360 
a = (360 – (6*d)) / 4 
where ‘a’ is the angle assumed in the beginning and ‘d’ is the common difference. 
 

Below is the implementation of the above approach: 
 

C++




// C++ implementation of the approach
#include <bits/stdc++.h>
#define ll long long int
using namespace std;
 
// Driver code
int main()
{
    int d = 10;
    double a;
 
    // according to formula derived above
    a = (double)(360 - (6 * d)) / 4;
 
    // print all the angles
    cout << a << ", " << a + d << ", " << a + (2 * d)
         << ", " << a + (3 * d) << endl;
    return 0;
}

Java




// java implementation of the approach
 
import java.io.*;
 
class GFG {
  
// Driver code
 
    public static void main (String[] args) {
            int d = 10;
    double a;
 
    // according to formula derived above
    a = (double)(360 - (6 * d)) / 4;
 
    // print all the angles
    System.out.print( a + ", " + (a + d) + ", " + (a + (2 * d))
        + ", " + (a + (3 * d)));
    }
}
//This code is contributed
//by  inder_verma

Python




# Python implementation
# of the approach
d = 10
a = 0.0
 
# according to formula
# derived above
a=(360 - (6 * d)) / 4
 
# print all the angles
print(a,",", a + d, ",", a + 2 * d,
        ",", a + 3 * d, sep = ' ')
 
# This code is contributed
# by sahilshelangia

C#




// C# implementation of the approach
using System;
 
class GFG
{
 
// Driver code
public static void Main ()
{
    int d = 10;
    double a;
     
    // according to formula derived above
    a = (double)(360 - (6 * d)) / 4;
     
    // print all the angles
    Console.WriteLine( a + ", " + (a + d) +
                           ", " + (a + (2 * d)) +
                           ", " + (a + (3 * d)));
}
}
 
// This code is contributed
// by anuj_67

PHP




<?php
// PHP implementation of the approach
 
// Driver code
$d = 10;
 
// according to formula
// derived above
$a = (360 - (6 * $d)) / 4 ;
 
// print all the angles
echo $a, ", ", $a + $d , ", ",
     $a + (2 * $d), ", ", $a + (3 * $d);
 
// This code is contributed
// by ANKITRAI1
?>

Javascript




<script>
 
// Javascript implementation of the approach
 
// Driver code
var d = 10;
var a;
 
// according to formula derived above
a = parseInt((360 - (6 * d)) / 4);
 
// print all the angles
document.write( a + ", " + (a + d) + ", " + (a + (2 * d))
    + ", " + (a + (3 * d)));
 
 
</script>

Time complexity: O(1)

Auxiliary Space: O(1)


My Personal Notes arrow_drop_up
Recommended Articles
Page :

Start Your Coding Journey Now!