Given that all the angles of a quadrilateral are in AP having common difference ‘d’, the task is to find all the angles.**Examples:**

Input: d = 10 Output: 75, 85, 95, 105 Input: d = 20 Output: 60, 80, 100, 120

**Approach:**

We know that the angles of the quadrilateral are in AP and having the common difference ‘d’.

So, if we assume the first angle to be ‘a’ then the other angles can be calculated as,

‘a+d’, ‘a+2d’ and ‘a+3d’

And, from the properties of quadrilaterals, the sum of all the angles of a quadrilateral is 360. So,

(a) + (a + d) + (a + 2*d) + (a + 3*d) = 360

4*a + 6*d = 360

a = (360 – (6*d)) / 4

where ‘a’ is the angle assumed in the beginning and ‘d’ is the common difference.

Below is the implementation of the above approach:

## C++

`// C++ implementation of the approach` `#include <bits/stdc++.h>` `#define ll long long int` `using` `namespace` `std;` `// Driver code` `int` `main()` `{` ` ` `int` `d = 10;` ` ` `double` `a;` ` ` `// according to formula derived above` ` ` `a = (` `double` `)(360 - (6 * d)) / 4;` ` ` `// print all the angles` ` ` `cout << a << ` `", "` `<< a + d << ` `", "` `<< a + (2 * d)` ` ` `<< ` `", "` `<< a + (3 * d) << endl;` ` ` `return` `0;` `}` |

## Java

`// java implementation of the approach` `import` `java.io.*;` `class` `GFG {` ` ` `// Driver code` ` ` `public` `static` `void` `main (String[] args) {` ` ` `int` `d = ` `10` `;` ` ` `double` `a;` ` ` `// according to formula derived above` ` ` `a = (` `double` `)(` `360` `- (` `6` `* d)) / ` `4` `;` ` ` `// print all the angles` ` ` `System.out.print( a + ` `", "` `+ (a + d) + ` `", "` `+ (a + (` `2` `* d))` ` ` `+ ` `", "` `+ (a + (` `3` `* d)));` ` ` `}` `}` `//This code is contributed` `//by inder_verma` |

## Python

`# Python implementation` `# of the approach` `d ` `=` `10` `a ` `=` `0.0` `# according to formula` `# derived above` `a` `=` `(` `360` `-` `(` `6` `*` `d)) ` `/` `4` `# print all the angles` `print` `(a,` `","` `, a ` `+` `d, ` `","` `, a ` `+` `2` `*` `d,` ` ` `","` `, a ` `+` `3` `*` `d, sep ` `=` `' '` `)` `# This code is contributed` `# by sahilshelangia` |

## C#

`// C# implementation of the approach` `using` `System;` `class` `GFG` `{` `// Driver code` `public` `static` `void` `Main ()` `{` ` ` `int` `d = 10;` ` ` `double` `a;` ` ` ` ` `// according to formula derived above` ` ` `a = (` `double` `)(360 - (6 * d)) / 4;` ` ` ` ` `// print all the angles` ` ` `Console.WriteLine( a + ` `", "` `+ (a + d) +` ` ` `", "` `+ (a + (2 * d)) +` ` ` `", "` `+ (a + (3 * d)));` `}` `}` `// This code is contributed` `// by anuj_67` |

## PHP

`<?php` `// PHP implementation of the approach` `// Driver code` `$d` `= 10;` `// according to formula` `// derived above` `$a` `= (360 - (6 * ` `$d` `)) / 4 ;` `// print all the angles` `echo` `$a` `, ` `", "` `, ` `$a` `+ ` `$d` `, ` `", "` `,` ` ` `$a` `+ (2 * ` `$d` `), ` `", "` `, ` `$a` `+ (3 * ` `$d` `);` `// This code is contributed` `// by ANKITRAI1` `?>` |

## Javascript

`<script>` `// Javascript implementation of the approach` `// Driver code` `var` `d = 10;` `var` `a;` `// according to formula derived above` `a = parseInt((360 - (6 * d)) / 4);` `// print all the angles` `document.write( a + ` `", "` `+ (a + d) + ` `", "` `+ (a + (2 * d))` ` ` `+ ` `", "` `+ (a + (3 * d)));` `</script>` |

**Output:**

75, 85, 95, 105

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