# Program to find remainder when large number is divided by r

Given a Number N, the task is to find the Remainder when N is divided by R (a two digit Number). The input of the Number may be very large.

Examples:

```Input: N = 13589234356546756, R = 13
Output: 11

Input: N = 3435346456547566345436457867978, R = 17
Output: 13
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

• Get the digit of N one by one from left to right.
• For each digit, combine with next digit if its less than R.
• If the combination at any point reaches above R, take and store the Remainder.
• Repeat the above steps for all digits from left to right.

Below is the program that implements the above approach:

## C++

 `// CPP implementation to find Remainder ` `// when a large Number is divided by R ` ` `  `#include ` `using` `namespace` `std; ` ` `  `// Function to Return Remainder ` `int` `Remainder(string str, ``int` `R) ` `{ ` `    ``// len is variable to store the ` `    ``// length of Number string. ` `    ``int` `len = str.length(); ` ` `  `    ``int` `Num, Rem = 0; ` ` `  `    ``// loop that find Remainder ` `    ``for` `(``int` `i = 0; i < len; i++) { ` ` `  `        ``Num = Rem * 10 + (str[i] - ``'0'``); ` `        ``Rem = Num % R; ` `    ``} ` ` `  `    ``// Return the remainder ` `    ``return` `Rem; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` ` `  `    ``// Get the large number as string ` `    ``string str = ``"13589234356546756"``; ` ` `  `    ``// Get the divisor R ` `    ``int` `R = 13; ` ` `  `    ``// Find and print the remainder ` `    ``cout << Remainder(str, R); ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java implementation to find Remainder ` `// when a large Number is divided by R ` ` `  `class` `GFG ` `{ ` `    ``// Function to Return Remainder ` `    ``static` `int` `Remainder(String str, ``int` `R) ` `    ``{ ` `        ``// len is variable to store the ` `        ``// length of Number string. ` `        ``int` `len = str.length(); ` `     `  `        ``int` `Num, Rem = ``0``; ` `     `  `        ``// loop that find Remainder ` `        ``for` `(``int` `i = ``0``; i < len; i++) { ` `     `  `            ``Num = Rem * ``10` `+ (str.charAt(i) - ``'0'``); ` `            ``Rem = Num % R; ` `        ``} ` `     `  `        ``// Return the remainder ` `        ``return` `Rem; ` `    ``} ` `     `  `    ``// Driver code ` `    ``public` `static` `void` `main( String [] args) ` `    ``{ ` `     `  `        ``// Get the large number as string ` `        ``String str = ``"13589234356546756"``; ` `     `  `        ``// Get the divisor R ` `        ``int` `R = ``13``; ` `     `  `        ``// Find and print the remainder ` `        ``System.out.println(Remainder(str, R)); ` `     `  `         `  `    ``} ` `} ` ` `  `// This code is contributed ` `// by ihritik `

## Python 3

 `# Python 3 implementation to  ` `# find Remainder when a large ` `# Number is divided by R ` ` `  `# Function to Return Remainder ` `def` `Remainder(``str``, R):  ` ` `  `    ``# len is variable to store the ` `    ``# length of Number string. ` `    ``l ``=` `len``(``str``) ` ` `  `    ``Rem ``=` `0` ` `  `    ``# loop that find Remainder ` `    ``for` `i ``in` `range``(l): ` ` `  `        ``Num ``=` `Rem ``*` `10` `+` `(``ord``(``str``[i]) ``-`  `                          ``ord``(``'0'``)) ` `        ``Rem ``=` `Num ``%` `R ` ` `  `    ``# Return the remainder ` `    ``return` `Rem ` ` `  `# Driver code ` `if` `__name__ ``=``=` `"__main__"``: ` ` `  `    ``# Get the large number  ` `    ``# as string ` `    ``str` `=` `"13589234356546756"` ` `  `    ``# Get the divisor R ` `    ``R ``=` `13` ` `  `    ``# Find and print the remainder ` `    ``print``(Remainder(``str``, R)) ` ` `  `# This code is contributed  ` `# by ChitraNayal `

## C#

 `// C# implementation to find  ` `// Remainder when a large ` `// Number is divided by R ` `using` `System; ` ` `  `class` `GFG ` `{ ` `     `  `// Function to Return Remainder ` `static` `int` `Remainder(String str,  ` `                     ``int` `R) ` `{ ` `    ``// len is variable to store the ` `    ``// length of Number string. ` `    ``int` `len = str.Length; ` ` `  `    ``int` `Num, Rem = 0; ` ` `  `    ``// loop that find Remainder ` `    ``for` `(``int` `i = 0; i < len; i++)  ` `    ``{ ` `        ``Num = Rem * 10 + (str[i] - ``'0'``); ` `        ``Rem = Num % R; ` `    ``} ` ` `  `    ``// Return the remainder ` `    ``return` `Rem; ` `} ` ` `  `// Driver code ` `public` `static` `void` `Main() ` `{ ` ` `  `    ``// Get the large number as string ` `    ``String str = ``"13589234356546756"``; ` ` `  `    ``// Get the divisor R ` `    ``int` `R = 13; ` ` `  `    ``// Find and print the remainder ` `    ``Console.WriteLine(Remainder(str, R)); ` `} ` `} ` ` `  `// This code is contributed ` `// by Subhadeep `

## PHP

 `

Output:

```11
```

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