Given an n x n grid, count squares in it.
Input: n = 2 Output: 5 (4 squares of 1 unit + 1 square of 2 units) Input: n = 3 Output: 14 (9 squares of 1 unit + 4 square of 2 units + 1 square of 1 unit)
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For a grid of size n*n the total number of squares formed are
1^2 + 2^2 + 3^2 + … + n^2 = n(n+1)(2n+1) / 6
Below is the implementation of above formula. Since the value of n*(n+1)*(2n+1) can cause overflow for large values of n, below are some interesting tricks used in the program.
1) long int is used in return.
2) n * (n + 1) / 2 is evaluated first as the value n*(n+1) will always be a multiple of 2.
Note that overflow may still happen, but above tricks just reduce chances of overflow.
Count of squares is 30
This article is contributed by Rishabh. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above
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