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Program to find number of solutions in Quadratic Equation

  • Last Updated : 22 Apr, 2021

Given an equation ax^{2}\pm bx\pm c=0  with value a, b, and c, where a and b is any value and c is constant, find how many solutions thus this quadratic equation have?
Examples: 
 

Input : 2x^{2}+5x+2=0
Output : 2 solutions
Input : x^{2}+x+1=0
Output : no solution

Solution: 
To check whether the equation has a solution or not, quadratic formula for discriminant is used.
 

The formula is given as, b^{2}-4ac

Respective conditions are given as, 
 

  • if the discriminant is positive b^{2}-4ac> 0  , then the quadratic equation has two solutions.
  • if the discriminant is equal b^{2}-4ac= 0  , then the quadratic equation has one solution.
  • if the discriminant is negative b^{2}-4ac< 0  , then the quadratic equation has no solution.

Programs: 
 



C++




// C++ Program to find the solutions of specified equations
#include <iostream>
using namespace std;
 
// Method to check for solutions of equations
void checkSolution(int a, int b, int c)
{
 
    // If the expression is greater than 0, then 2 solutions
    if (((b * b) - (4 * a * c)) > 0)
        cout << "2 solutions";
 
    // If the expression is equal 0, then 2 solutions
    else if (((b * b) - (4 * a * c)) == 0)
        cout << "1 solution";
 
    // Else no solutions
    else
        cout << "No solutions";
}
 
int main()
{
    int a = 2, b = 5, c = 2;
    checkSolution(a, b, c);
    return 0;
}

Java




// Java Program to find the solutions of specified equations
public class GFG {
 
    // Method to check for solutions of equations
    static void checkSolution(int a, int b, int c)
    {
 
        // If the expression is greater than 0,
        // then 2 solutions
        if (((b * b) - (4 * a * c)) > 0)
            System.out.println("2 solutions");
 
        // If the expression is equal 0, then 2 solutions
        else if (((b * b) - (4 * a * c)) == 0)
            System.out.println("1 solution");
 
        // Else no solutions
        else
            System.out.println("No solutions");
    }
 
    // Driver Code
    public static void main(String[] args)
    {
        int a = 2, b = 5, c = 2;
        checkSolution(a, b, c);
    }
}

Python3




# Python3 Program to find the
# solutions of specified equations
 
# function to check for
# solutions of equations
def checkSolution(a, b, c) :
 
    # If the expression is greater
    # than 0, then 2 solutions
    if ((b * b) - (4 * a * c)) > 0 :
        print("2 solutions")
 
    # If the expression is equal 0,
    # then 1 solutions
    elif ((b * b) - (4 * a * c)) == 0 :
        print("1 solution")
 
    # Else no solutions
    else :
        print("No solutions")
 
# Driver code
if __name__ == "__main__" :
 
    a, b, c = 2, 5, 2
    checkSolution(a, b, c)
 
# This code is contributed
# by ANKITRAI1

C#




// C# Program to find the solutions
// of specified equations
using System;
class GFG
{
 
// Method to check for solutions of equations
static void checkSolution(int a, int b, int c)
{
 
    // If the expression is greater
    // than 0, then 2 solutions
    if (((b * b) - (4 * a * c)) > 0)
        Console.WriteLine("2 solutions");
 
    // If the expression is equal to 0,
    // then 2 solutions
    else if (((b * b) - (4 * a * c)) == 0)
        Console.WriteLine("1 solution");
 
    // Else no solutions
    else
        Console.WriteLine("No solutions");
}
 
// Driver Code
public static void Main()
{
    int a = 2, b = 5, c = 2;
    checkSolution(a, b, c);
}
}
 
// This code is contributed by inder_verma

PHP




<?php
// Program to find the solutions
// of specified equations
 
// Method to check for solutions
// of equations
function checkSolution($a, $b, $c)
{
 
    // If the expression is greater
    // than 0, then 2 solutions
    if ((($b * $b) - (4 * $a * $c)) > 0)
        echo "2 solutions";
 
    // If the expression is equal 0,
    // then 2 solutions
    else if ((($b * $b) -
              (4 * $a * $c)) == 0)
        echo "1 solution";
 
    // Else no solutions
    else
        echo"No solutions";
}
 
// Driver Code
$a = 2; $b = 5; $c = 2;
checkSolution($a, $b, $c);
 
// This code is contributed
// by inder_verma
?>

Javascript




<script>
 
// Javascript Program to find the solutions
// of specified equations
 
// Method to check for solutions of equations
function checkSolution(a, b, c)
{
     
    // If the expression is greater than 0,
    // then 2 solutions
    if (((b * b) - (4 * a * c)) > 0)
        document.write("2 solutions");
 
    // If the expression is equal 0, then 2 solutions
    else if (((b * b) - (4 * a * c)) == 0)
        document.write("1 solution");
 
    // Else no solutions
    else
        document.write("No solutions");
}
 
// Driver Code
var a = 2, b = 5, c = 2;
 
checkSolution(a, b, c);
 
// This code is contributed by Ankita saini
 
</script>

Output: 

2 solutions

 

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