Program to find Nth term of the series 2, 4, 3, 4, 15…

Given a number N. The task is to write a program to find the Nth term in the below series:

2, 4, 3, 4, 15...

Examples:

Input: N = 5
Output: 15
Explanation:
For N = 5,
Nth term = ( N * ( (N%2) + (N%3) ) 
         = ( 5 * ( (5%2) + (5%3) ) 
         = ( 5 * ( 1 + 2 )
         = 15

Input: N = 4 
Output: 4

Generalized Nth term of this series:



Nth term = ( N * ( (N%2) + (N%3) ) )

Below is the implementation of the above approach:

C++

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// CPP program to find N-th term of the series:
// 2, 4, 3, 4, 15...
  
#include <iostream>
using namespace std;
  
// function to calculate Nth term of series
int nthTerm(int N)
{
    // By using above formula
    return (N * ((N % 2) + (N % 3)));
}
  
// Driver Function
int main()
{
  
    // get the value of N
    int N = 5;
  
    // Calculate and print the Nth term
    cout << "Nth term for N = "
         << N << " : "
         << nthTerm(N);
  
    return 0;
}

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Java

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import java.io.*;
  
// Class to calculate Nth term of series
class Nth {
    public int nthTerm(int N)
    {
        // By using above formula
        return (N * ((N % 2) + (N % 3)));
    }
}
  
// Main class for main method
class GFG {
  
    public static void main(String[] args)
    {
  
        // get the value of N
        int N = 5;
  
        // create object of Class Nth
        Nth a = new Nth();
  
        // Calculate and print the Nth term
        System.out.println("Nth term for N = "
                           + N + " : "
                           + a.nthTerm(N));
    }
}

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Python3

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# Python3 program to find N-th term of the series:
# 2, 4, 3, 4, 15...
  
  
  
# function to calculate Nth term of series
def nthTerm( N):
  
    # By using above formula
    return (N * ((N % 2) + (N % 3)))
  
  
# Driver Function
  
  
# get the value of N
if __name__=='__main__':
    N = 5
  
    # Calculate and pr the Nth term
    print("Nth term for N = ", N , " : ",nthTerm(N))
  
# This code is contributed by ash264

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C#

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// C# program to find 
// N-th term of the series:
// 2, 4, 3, 4, 15...
using System;
  
class GFG
{
public int nthTerm(int N)
{
    // By using above formula
    return (N * ((N % 2) + (N % 3)));
}
  
public static void Main()
{
  
    // get the value of N
    int N = 5;
  
    GFG a = new GFG();
  
    // Calculate and print the Nth term
    Console.Write("Nth term for N = "
                            N + " : "
                         a.nthTerm(N));
}
}
  
// This code is contributed 
// by ChitraNayal

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PHP

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<?php
// PHP program to find 
// N-th term of the series: 
// 2, 4, 3, 4, 15...
  
function nthTerm($N)
{
    return ($N * (($N % 2) + ($N % 3)));
}
  
// Driver code
$N = 5 ;
  
echo "Nth term for N = " . $N
          " : " . nthTerm($N) ;
  
// This code is contributed by ANKITRAI1
?>

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Output:

Nth term for N = 5 : 15

Time Complexity: O(1)



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Improved By : ash264, AnkitRai01, chitranayal