Program to find Nth term of the series 2, 4, 3, 4, 15…

Given a number N. The task is to write a program to find the Nth term in the below series:

2, 4, 3, 4, 15...

Examples:

Input: N = 5
Output: 15
Explanation:
For N = 5,
Nth term = ( N * ( (N%2) + (N%3) )
= ( 5 * ( (5%2) + (5%3) )
= ( 5 * ( 1 + 2 )
= 15

Input: N = 4
Output: 4

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Generalized Nth term of this series:

Nth term = ( N * ( (N%2) + (N%3) ) )

Below is the implementation of the above approach:

C++

 // CPP program to find N-th term of the series: // 2, 4, 3, 4, 15...    #include using namespace std;    // function to calculate Nth term of series int nthTerm(int N) {     // By using above formula     return (N * ((N % 2) + (N % 3))); }    // Driver Function int main() {        // get the value of N     int N = 5;        // Calculate and print the Nth term     cout << "Nth term for N = "          << N << " : "          << nthTerm(N);        return 0; }

Java

 import java.io.*;    // Class to calculate Nth term of series class Nth {     public int nthTerm(int N)     {         // By using above formula         return (N * ((N % 2) + (N % 3)));     } }    // Main class for main method class GFG {        public static void main(String[] args)     {            // get the value of N         int N = 5;            // create object of Class Nth         Nth a = new Nth();            // Calculate and print the Nth term         System.out.println("Nth term for N = "                            + N + " : "                            + a.nthTerm(N));     } }

Python3

 # Python3 program to find N-th term of the series: # 2, 4, 3, 4, 15...          # function to calculate Nth term of series def nthTerm( N):        # By using above formula     return (N * ((N % 2) + (N % 3)))       # Driver Function       # get the value of N if __name__=='__main__':     N = 5        # Calculate and pr the Nth term     print("Nth term for N = ", N , " : ",nthTerm(N))    # This code is contributed by ash264

C#

 // C# program to find  // N-th term of the series: // 2, 4, 3, 4, 15... using System;    class GFG { public int nthTerm(int N) {     // By using above formula     return (N * ((N % 2) + (N % 3))); }    public static void Main() {        // get the value of N     int N = 5;        GFG a = new GFG();        // Calculate and print the Nth term     Console.Write("Nth term for N = " +                              N + " : " +                           a.nthTerm(N)); } }    // This code is contributed  // by ChitraNayal

PHP



Output:

Nth term for N = 5 : 15

Time Complexity: O(1)

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Improved By : ash264, AnkitRai01, chitranayal