Given a number N. The task is to write a program to find the Nth term of the below series:
0, 7, 18, 33, 51, 75, 102, 133, …(N Terms)
Examples:
Input: N = 4 Output: 33 For N = 4 4th Term = ( 2 * 4 * 4 + 4 - 3) = 33 Input: N = 10 Output: 206
Approach: The generalized Nth term of this series:
Below is the required implementation:
C++
// C++ program to find the N-th term of the series: // 0, 7, 18, 33, 51, 75, 102, ..... #include <iostream> #include <math.h> using namespace std;
// calculate Nth term of series int nthTerm( int n)
{ return 2 * pow (n, 2) + n - 3;
} // Driver code int main()
{ int N = 4;
cout << nthTerm(N) << endl;
return 0;
} |
Java
// Java program to find the N-th term of the series: // 0, 7, 18, 33, 51, 75, 102, ..... import java.io.*;
class GFG {
// calculate Nth term of series static int nthTerm( int n)
{ return 2 * ( int )Math.pow(n, 2 ) + n - 3 ;
} // Driver code public static void main (String[] args) {
int N = 4 ;
System.out.println( nthTerm(N));
}
} // This code is contributed // by anuj_67.. |
Python3
# Python3 program to find the # N-th term of the series: # 0, 7, 18, 33, 51, 75, 102, ..... # calculate Nth term of series def nthTerm(n):
return 2 * pow (n, 2 ) + n - 3
# Driver code N = 4
print (nthTerm(N))
# This code is contributed by # Sanjit_Prasad |
C#
// C# program to find the // N-th term of the series: // 0, 7, 18, 33, 51, 75, 102, ..... using System;
class GFG
{ // calculate Nth term of series static int nthTerm( int n)
{ return 2 * ( int )Math.Pow(n, 2) + n - 3;
} // Driver code public static void Main ()
{ int N = 4;
Console.Write( nthTerm(N));
} } // This code is contributed // by ChitraNayal |
PHP
<?php // PHP program to find the // N-th term of the series: // 0, 7, 18, 33, 51, 75, 102,... // calculate Nth term of series function nthTerm( $n )
{ return 2 * pow( $n , 2) + $n - 3;
} // Driver code $N = 4;
echo nthTerm( $N ) + "\n" ;
// This code is contributed // by Akanksha Rai(Abby_akku) ?> |
Javascript
<script> // JavaScript program to find the N-th term of the series: // 0, 7, 18, 33, 51, 75, 102, ..... // calculate Nth term of series function nthTerm( n)
{ return 2 * Math.pow(n, 2) + n - 3;
} // Driver code let N = 4; document.write( nthTerm(N) );
// This code contributed by gauravrajput1 </script> |
Output:
33
Time Complexity: O(1)
Auxiliary Space: O(1) since using constant variables