Program to find Nth term of series 0, 7, 18, 33, 51, 75, 102, 133, …..
Given a number N. The task is to write a program to find the Nth term of the below series:
0, 7, 18, 33, 51, 75, 102, 133, …(N Terms)
Examples:
Input: N = 4
Output: 33
For N = 4
4th Term = ( 2 * 4 * 4 + 4 - 3)
= 33
Input: N = 10
Output: 206
Approach: The generalized Nth term of this series:
Below is the required implementation:
C++
#include <iostream>
#include <math.h>
using namespace std;
int nthTerm( int n)
{
return 2 * pow (n, 2) + n - 3;
}
int main()
{
int N = 4;
cout << nthTerm(N) << endl;
return 0;
}
|
Java
import java.io.*;
class GFG {
static int nthTerm( int n)
{
return 2 * ( int )Math.pow(n, 2 ) + n - 3 ;
}
public static void main (String[] args) {
int N = 4 ;
System.out.println( nthTerm(N));
}
}
|
Python3
def nthTerm(n):
return 2 * pow (n, 2 ) + n - 3
N = 4
print (nthTerm(N))
|
C#
using System;
class GFG
{
static int nthTerm( int n)
{
return 2 * ( int )Math.Pow(n, 2) + n - 3;
}
public static void Main ()
{
int N = 4;
Console.Write( nthTerm(N));
}
}
|
PHP
<?php
function nthTerm( $n )
{
return 2 * pow( $n , 2) + $n - 3;
}
$N = 4;
echo nthTerm( $N ) + "\n" ;
?>
|
Javascript
<script>
function nthTerm( n)
{
return 2 * Math.pow(n, 2) + n - 3;
}
let N = 4;
document.write( nthTerm(N) );
</script>
|
Time Complexity: O(1)
Auxiliary Space: O(1) since using constant variables
Last Updated :
05 Aug, 2022
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