Program to find greater value between a^n and b^n

• Last Updated : 04 May, 2021

Given three integers a, b and n, the task is to find out greater value between an and bn.
Examples:

Input: a = 3, b = 4, n = 5
Output: b^n is greater than a^n
Value of an is 243 and the value of bn is 1024.
So, bn is greater than an.
Input: a = -3, b = 2, n = 4
Output: a^n is greater than b^n
Value of an is 243 and the value of bn is 16.
So, an is greater than bn

Basic Approach: For every value of a, b and n, calculate the values of an and bn. Then compare the result obtained and display the according to output.
The problem with this approach arises when there are large values of a, b and n. For large values of a, n, calculating an can exceed the limit of integer which will cause integer overflow.
Better approach is to check the value of n.

• If n is even then calculate the absolute value of a and b.
• If n is odd then take the given value as it is.
• Now check if a is equal to b. If yes, print 0.
• If a is greater than b, print 1.
• Otherwise, print 2.

C++

 // C++ code for finding greater// between the a^n and b^n#include using namespace std; // Function to find the greater valuevoid findGreater(int a, int b, int n){    // If n is even    if (!(n & 1)) {         a = abs(a);        b = abs(b);    }    if (a == b)        cout << "a^n is equal to b^n";     else if (a > b)        cout << "a^n is greater than b^n";     else        cout << "b^n is greater than a^n";} // Driver codeint main(){    int a = 12, b = 24, n = 5;    findGreater(a, b, n);    return 0;}

Java

 // JAVA code for finding greater// between the a^n and b^nimport java.io.*; class GFG{    // Function to find    // the greater value    static void findGreater(int a,                            int b, int n){    // If n is even    if (!((n & 1) > 0))    {         a = Math.abs(a);        b = Math.abs(b);    }    if (a == b)        System.out.println("a^n is " +                           "equal to b^n");     else if (a > b)        System.out.println("a^n is greater " +                                  "than b^n");     else        System.out.println("b^n is greater " +                                  "than a^n");} // Driver codepublic static void main (String[] args){int a = 12, b = 24, n = 5;findGreater(a, b, n);}} // This code is contributed// by shiv_bhakt.

Python3

 # Python3 code for finding greater# between the a^n and b^nimport math # Function to find the greater valuedef findGreater(a, b, n):     # If n is even    if ((n & 1) > 0):         a = abs(a);        b = abs(b);    if (a == b):        print("a^n is equal to b^n");     elif (a > b):        print("a^n is greater than b^n");     else:        print("b^n is greater than a^n"); # Driver codea = 12;b = 24;n = 5;findGreater(a, b, n); # This code is contributed by mits

C#

 // C# code for finding greater// between the a^n and b^nusing System; class GFG{    // Function to find    // the greater value    static void findGreater(int a,                            int b,                            int n)    {    // If n is even    if (!((n & 1) > 0))    {         a = Math.Abs(a);        b = Math.Abs(b);    }         if (a == b)        Console.WriteLine("a^n is " +                          "equal to b^n");     else if (a > b)        Console.WriteLine("a^n is greater " +                                 "than b^n");     else        Console.WriteLine("b^n is greater " +                                 "than a^n");} // Driver codepublic static void Main(){    int a = 12, b = 24, n = 5;    findGreater(a, b, n);}} // This code is contributed// by shiv_bhakt.

PHP

 \$b)        echo "a^n is greater than b^n";     else        echo "b^n is greater than a^n";} // Driver code\$a = 12; \$b = 24; \$n = 5;findGreater(\$a, \$b, \$n); // This code is contributed by ajit?>

Javascript


Output:
b^n is greater than a^n

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