Given a singly linked list. The task is to find the average of all nodes of the given singly linked list.
Input: 7->6->8->4->1 Output: 26 Average of nodes: (7 + 6 + 8 + 4 + 1 ) / 5 = 5.2 Input: 1->7->3->9->11->5 Output: 6
- Initialise a pointer ptr with the head of the linked list and a sum variable with 0.
- Start traversing the linked list using a loop until all the nodes get traversed.
- Add the value of current node to the sum i.e. sum += ptr -> data .
- Increment the pointer to the next node of linked list i.e. ptr = ptr ->next .
- Divide sum by total number of node and Return the average.
Below is the implementation of the above approach:
Average of nodes = 5.2
Time complexity : O(n)
Where n is equal to number of nodes.
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