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Program to convert Java Set to Stream in Scala

Last Updated : 29 Nov, 2019
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A java Set can be converted to a Stream in Scala by utilizing toStream method of Java in Scala. Here, we need to import Scala’s JavaConversions object in order to make this conversions work.
Now, let’s see some examples and then discuss how it works in details.
Example:1#




// Scala program to convert Java set 
// to Stream in Scala
  
// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._
  
// Creating object
object GfG
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating set in Java
        val set = new java.util.HashSet[Int]()
          
        // Adding integers to the set
        set.add(9)
        set.add(10)
        set.add(11)
          
        // Converting set to Stream 
        val stream= set.toStream
          
        // Displays Stream 
        println(stream)
      
    }
}


Output:

Stream(9, ?)

Therefore, a Stream is returned. Here, firstly a set is created where, integer elements are added to it utilizing add method. After that toStream method is utilized in order to convert the stated set to a Stream.
Example:2#




// Scala program to convert Java set 
// to a Stream in Scala
  
// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._
  
  
// Creating object
object GfG
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating set in Java
        val set = new java.util.HashSet[Int]()
          
        // Adding Integers to the set
        set.add(2)
        set.add(1)
        set.add(3)
          
        // Converting set to a Stream
        val stream = set.toStream
          
        // Displays Stream 
        println(stream)
      
    }
}


Output:

Stream(1, ?)

It is same as above example but here the elements of the set are not present in a proper order. But the stream returned is in proper order.



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