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Program to convert Java set of integers to an Indexed Sequence in Scala

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A java set of integers can be converted to an Indexed Sequence in Scala by utilizing toIndexedSeq method of Java in Scala. Here, you need to import Scala’s JavaConversions object in order to make this conversions work else an error will occur.
Now, lets see some examples and then discuss how it works in details.
Example:1#




// Scala program to convert Java set
// to an Indexed Sequence in Scala
  
// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._
  
  
// Creating object
object GfG
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating set of integers in Java
        val set = new java.util.HashSet[Int]()
          
        // Adding integers to the set
        set.add(9)
        set.add(10)
        set.add(11)
          
        // Converting set to an Indexed Sequence
        val ind = set.toIndexedSeq
          
        // Displays Indexed Sequence
        println(ind)
          
    }
}


Output:

Vector(9, 10, 11)

Therefore, an indexed sequence is returned.
Example:2#




// Scala program to convert Java set
// to an Indexed Sequence in Scala
  
// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._
  
// Creating object
object GfG
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating set of integers in Java
        val set = new java.util.HashSet[Int]()
          
        // Adding integers to the set
        set.add(7)
        set.add(3)
        set.add(9)
          
        // Converting set to an Indexed Sequence
        val ind = set.toIndexedSeq
          
        // Displays Indexed Sequence
        println(ind)
      
    }
}


Output:

Vector(3, 7, 9)

Here, the stated set is not stated in proper order but the resultant output is in proper order.


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Last Updated : 29 Dec, 2019
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