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Program to convert Java list to Seq in Scala
  • Last Updated : 29 Nov, 2019
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A java list can be converted to sequence in Scala by utilizing toSeq method of Java in Scala. Here, you need to import Scala’s JavaConversions object in order to make this conversions work else an error will occur.
Now, lets see some examples and then discuss how it works in details.
Example:1#




// Scala program to convert Java list 
// to Sequence in Scala
  
// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._
  
  
// Creating object
object GfG
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating list in Java
        val list = new java.util.ArrayList[Int]()
          
        // Adding integers to the list
        list.add(5)
        list.add(6)
          
        // Converting list to Sequence 
        val seq= list.toSeq
          
        // Displays seq
        println(seq)
      
    }
}
Output:
Buffer(5, 6)

Therefore, a sequence of integer is returned. Here, firstly a list is created where, the int elements are added to it utilizing add method. After that toSeq method is utilized in order to convert the stated list to a sequence.
Example:2#




// Scala program to convert Java list 
// to Seq in Scala
  
// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._
  
  
// Creating object
object GfG
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating list in Java
        val list = new java.util.ArrayList[Int]()
          
        // Adding integers to the list
        list.add(5)
        list.add(6)
        list.add(1)
          
        // Converting list to a sequence 
        val seq = list.toSeq
          
        // Displays seq
        println(seq)
      
    }
}
Output:
Buffer(5, 6, 1)

It is same as above example but here one more element is added in the stated list and then its returned here in the form of sequence.

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