Program to convert Java list of Strings to an Indexed Sequence in Scala
A java list of Strings can be converted to an Indexed Sequence in Scala by utilizing toIndexedSeq method of Java in Scala. Here, you need to import Scala’s JavaConversions object in order to make this conversions work else an error will occur.
Now, lets see some examples and then discuss how it works in details.
Example:1#
// Scala program to convert Java list // to an Indexed Sequence in Scala // Importing Scala's JavaConversions objectimport scala.collection.JavaConversions._ // Creating objectobject GfG{ // Main method def main(args:Array[String]) { // Creating list of Strings in Java val list = new java.util.ArrayList[String]() // Adding Strings to the list list.add("geeks") list.add("for") list.add("geeks") // Converting list to an Indexed Sequence val ind = list.toIndexedSeq // Displays Indexed Sequence println(ind) }} |
Output:
Vector(geeks, for, geeks)
Therefore, an indexed sequence is returned.
Example:2#
// Scala program to convert Java list // to an Indexed Sequence in Scala // Importing Scala's JavaConversions objectimport scala.collection.JavaConversions._ // Creating objectobject GfG{ // Main method def main(args:Array[String]) { // Creating list of Strings in Java val list = new java.util.ArrayList[String]() // Adding Strings to the list list.add("I") list.add("am an") list.add("author") // Converting list to an Indexed Sequence val ind = list.toIndexedSeq // Displays Indexed Sequence println(ind) }} |
Output:
Vector(I, am an, author)
Here, the stated list is not in proper order so the resultant output is also not in proper order. That is, the strings with more number of words are not displayed in the last, they are returned as stated in the list.
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