Program to convert Java list of integers to an Indexed Sequence in Scala

A java list can be converted to an Indexed Sequence in Scala by utilizing toIndexedSeq method of Java in Scala. Here, we need to import Scala’s JavaConversions object in order to make this conversions work else an error will occur.
Now, lets see some examples and then discuss how it works in details.
Example:1#

// Scala program to convert Java list
// to an Indexed Sequence in Scala

// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._


// Creating object
object GfG
{

    // Main method
    def main(args:Array[String])
    {

        // Creating list in Java
        val list = new java.util.ArrayList[Int]()

        // Adding integers to the list
        list.add(1)
        list.add(2)
        list.add(3)

        // Converting list to an Indexed Sequence
        val ind = list.toIndexedSeq

        // Displays Indexed Sequence
        println(ind)

    }
}

Output:

Vector(1, 2, 3)

Therefore, an indexed sequence is returned.
Example:2#

// Scala program to convert Java list
// to an Indexed Sequence in Scala

// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._


// Creating object
object GfG
{

    // Main method
    def main(args:Array[String])
    {

        // Creating list in Java
        val list = new java.util.ArrayList[Int]()

        // Adding integers to the list
        list.add(9)
        list.add(4)
        list.add(8)

        // Converting list to an Indexed Sequence
        val ind = list.toIndexedSeq

        // Displays Indexed Sequence
        println(ind)

    }
}

Output:

Vector(9, 4, 8)

Here, the stated list is not in proper order so the resultant output is also not in proper order.