Program to convert Java list of integers to an Indexed Sequence in Scala
A java list can be converted to an Indexed Sequence in Scala by utilizing toIndexedSeq method of Java in Scala. Here, we need to import Scala’s JavaConversions object in order to make this conversions work else an error will occur.
Now, lets see some examples and then discuss how it works in details.
Example:1#
import scala.collection.JavaConversions. _
object GfG
{
def main(args : Array[String])
{
val list = new java.util.ArrayList[Int]()
list.add( 1 )
list.add( 2 )
list.add( 3 )
val ind = list.toIndexedSeq
println(ind)
}
}
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Therefore, an indexed sequence is returned.
Example:2#
import scala.collection.JavaConversions. _
object GfG
{
def main(args : Array[String])
{
val list = new java.util.ArrayList[Int]()
list.add( 9 )
list.add( 4 )
list.add( 8 )
val ind = list.toIndexedSeq
println(ind)
}
}
|
Here, the stated list is not in proper order so the resultant output is also not in proper order.
Last Updated :
29 Dec, 2019
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